23x-13=2(x+2)
First you would distribute the 2 into the parenthesis
It will look like this after: 23x-13=2x+4
Then you would subtract 2x on both sides because u have to get the x's on one side
It will look like this after:21x-13=4
Then you would add 13 to both sides
It will look like this after: 21x=17
Then you would divide 21 on both sides
Your final product is 21/17
Once Youu Divide It Youu Go 524/9=58.222222... A lot Of 2's..
Hope This Helps Youu
Youur Welcome
If 5 biscuits cost 40p
1 biscuit would cost (40p divided by 5) 8p
8p multiplied by 3 (to get 3 biscuits) would cost 24p
3 biscuits cost 24p
Answer:
20/18
Step-by-step explanation:
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
