Are you solving for x or what
Answer:
144
Step-by-step explanation:
12x12=144
Answer:
P = 100
Area = 625
Step-by-step explanation:
Area = s^2
sqrt(area) = sqrt(s^2)
area = 25*25
sqrt(25*25) = sqrt(s^2)
s = 25
P = 4*s
P = 4 * 25
P = 100
Area = s^2
s = 25
Area = 25^2
Area = 625
Answer:
-23
Step-by-step explanation:
Let first negative integer = x
The second = x +5
Their product = 126, hence,
x * (x +5) = 126
x^2 + 5x = 126
x^2 + 5x - 126 = 0
Two numbers whose product gives - 126 and sun gives 5
x(x + 14) - 9(x+14) =0
(x - 9) = 0 or (x + 14) = 0
x = 9 or x = - 14
Since x is said to be a negative integer,, the our x = - 14
First integer = - 14
Second integer = (x + 5) = (-14 + 5) = - 9
Sum of both integers :
-14 + - 9 = - 23
recall d = rt, distance = rate * time.
let's say airplane A is going at a rate of "r", therefore airplane B is moving faster, at a rate of "r + 80".
now, after 3 hours, both planes have been travelling for 3 hours each, and say if A has covered "d" miles, then B has covered the slack of 2490 - d.
![\bf \leftarrow \underset{A}{\stackrel{r}{\rule[0.22em]{8em}{0.25pt}}}dallas\underset{B}{\stackrel{r+80}{\rule[0.22em]{18em}{0.25pt}}}\to \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ plane~A&d&r&3\\ plane~B&2490-d&r+80&3 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cleftarrow%20%5Cunderset%7BA%7D%7B%5Cstackrel%7Br%7D%7B%5Crule%5B0.22em%5D%7B8em%7D%7B0.25pt%7D%7D%7Ddallas%5Cunderset%7BB%7D%7B%5Cstackrel%7Br%2B80%7D%7B%5Crule%5B0.22em%5D%7B18em%7D%7B0.25pt%7D%7D%7D%5Cto%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20plane~A%26d%26r%263%5C%5C%20plane~B%262490-d%26r%2B80%263%20%5Cend%7Barray%7D)
