Using pv=nRT
T= 22+273 K
P=1.15 Pa
R=8.31
V =5.5... (u did not write the unit so...)
Therefore n,mole= (1.15×5.5) ÷ (273+22)(8.31)
Answer:
the mass of CaO present at equilibrium is, 0.01652g
Explanation:
= 3.8×10⁻²
Now we have to calculate the moles of CO₂
Using ideal gas equation,
PV =nRT
P = pressure of gas = 3.8×10⁻²
T = temperature of gas = 1000 K
V = volume of gas = 0.638 L
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mole.k

Now we have to calculate the mass of CaO
mass = 2.95 * 10 ⁻⁴ × 56
= 0.01652g
Therefore,
the mass of CaO present at equilibrium is, 0.01652g
<span>Amino acids which are known to be linked by peptide bonds they form polypeptide chains.
Proteins are linear polymers are formed by way of linking an a-carboxy group of one amino acid to a-amino of different amino acids which have peptide bond. The formation which results from two amino acids which result in a loss of a water molecule. The best process of the reaction is hydrolysis.</span>