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timama [110]
3 years ago
12

How many moles of sulfuric acid (H2SO4) are present in 500.0 mL of 0.15 M H2SO4 solution?

Chemistry
1 answer:
galben [10]3 years ago
7 0

Answer:

Number of moles = 0.075 mol

Explanation:

Volume = 500.0 mL = 0.5 (Converting to L by dividing by 1000)

Molarity = 0.15 M

Number of moles = ?

The relationship between the quantities is given as;

Molarity  = Number of moles / Volume

Number of moles = Molarity * Volume

Number of moles = 0.15  * 0.5

Number of moles = 0.075 mol

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2. 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
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Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

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<em />

100g of each reactant are:

AgNO₃: 100g × (1mol / 169.87g) = 0.589 moles

CaCl₂: 100g × (1mol / 110.98g) = 0.901 moles

For a complete reaction of 0.901 moles of CaCl₂ are necessaries 0.901×2 = <em>1.802 moles of AgNO₃. </em>As there are just 0.589moles, <em>AgNO₃ is limitng reactant</em>

<em></em>

0.589 moles of AgNO₃ produce:

0.589 moles × ( 2 moles AgCl / 2 moles AgNO₃) =

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3 0
4 years ago
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