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Sladkaya [172]
3 years ago
6

Tickets for a school play sold for $7.50 for each adult and $3.00 for each child. The total receipts for 118 tickets totaled $69

6. Find the number of adult tickets sold.
adult tickets
Mathematics
1 answer:
NeX [460]3 years ago
7 0
X= number of adult tickets
y=number of child tickets.
we can suggest this system of equations: 
x+y=118                 ⇒x=118-y
7.5x+3y=696

we can solve this system of equations by substitution method:
7.5(118-y)+3y=696
885-7.5y+3y=696
-4.5y=-189
y=-189/-4.5
y=42

x=118-y
x=118-42
x=76

Answer: the number of adult tickets sold was 76. 
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Chase and his brother like to play basketball. About a month ago they decided to keep track of how many games they have each won
Anettt [7]

Answer:

Step-by-step explanation:

As of today, Chase has won 18 out of 30 games against his brother. The percentage of games that he has won as of today is

18/30 × 100 = 60%

In order to get 75% wins, let the number of games would be x. Then

(18 + x)/(30 + x) × 100 = 75

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chase has to win 18 games in a row.

In order to get 90% wins, let the number of games would be y. Then

(18 + x)/(30 + x) × 100 = 90

100(18 + x) = 90(30 + x)

1800 + 100x = 2700 + 75x

100x - 75x = 2700 - 1800

25x = 900

x = 900/25 = 36

chase has to win 36 games in a row in order to have a 90% winning record.

(18 + x)/(30 + x) × 100 = 100

100(1800 + x) = 100(30 + x)

1800 + 100x = 3000 + 100x

100x - 100x = 3000 - 1800

Therefore, it is impossible to for chase to reach a 100% winning record because he has already had some losses.

2) for a wining record of 90, the total number of games played is

30 + 36 = 66 games and the total number of wins was 18 + 36 = 54

In order to get 55% losses, let the number of games would be z. Then

(54 + z)/(66 + z) × 100 = 55

100(54 + z) = 55(66 + z)

5400 + 100z = 3630 + 55z

100z - 55z = 3630 - 5400

45z = - 1770

z = - 1770/45 = - 40

chase has to lose 40 games in a row in order to drop down to a winning record below 55% again.

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