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2 years ago

8

Hey.... what's

" id="TexFormula1" title="x {}^{2} \: \: where \: x = 5" alt="x {}^{2} \: \: where \: x = 5" align="absmiddle" class="latex-formula">

2 answers:

trasher [3.6K]2 years ago

4 0

5^2 = 25
So that’s 5x5
The answer is 25

ryzh [129]2 years ago

4 0

Answer:

x = 25

thanks hope it helps

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Roberta jogs 3 laps the first day, 5 laps the second day, 7 laps the third, and so on. On which day will Roberta jog 13 laps if

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It seems that she runs two more laps each day, so:

day 1- 3

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3 years ago

Please help I need help on this

LiRa [457]

1×10+7×1+6×0.1+0×0.01+1×0.001 is the answer

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2 years ago

Find the value of x?

Burka [1]

Answer:

<em>We </em><em>know </em><em>that </em><em>the </em><em>exterior </em><em>angle </em><em>of </em><em>a </em><em>triangle </em><em>is </em><em>equal </em><em>to </em><em>the </em><em>sum </em><em>of </em><em>two </em><em>opposite</em><em> </em><em>interior </em><em>angle. </em>

Step-by-step explanation:

So

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57 = 45x - 26x

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3 years ago

Granger walks 2 1/5 miles in 2/3 an hour at a constant speed.

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3 years ago

Solve for n in the literal equation a(n-2)+5=bn

Helga [31]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>a(n-2)+5=bn</u></em>

<em><u>Add -bn to both sides</u></em>

<em><u>an-2a+5+(-bn)=bn+(-bn)</u></em>

<em><u>an-bn-2a+5=0</u></em>

<em><u>add two a to both sides</u></em>

<em><u>an−bn−2a+5+(2a)=0+(2a)</u></em>

<em><u>an−bn+5=2a</u></em>

<em><u>Add -5 to both sides</u></em>

<em><u>an−bn+5+(-5)=2a+(-5)</u></em>

<em><u>an−bn=2a−5</u></em>

<em><u>Factor out our variable</u></em>

<em><u>n(a−b)=2a−5</u></em>

<em><u>Divide both sides by a-b</u></em>

<em><u>n(a-b)/a-b=2a-5/a-b</u></em>

<em><u>n=2a-5/a-b</u></em>

<em><u>Hope this helps</u></em>

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3 years ago