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torisob [31]
3 years ago
8

The expression square root 5x is equivalent to the expression square root 5 A. True Or B. False

Mathematics
2 answers:
sveticcg [70]3 years ago
7 0

Answer:

false

Step-by-step explanation:

Kitty [74]3 years ago
4 0

Answer:

False

Step-by-step explanation:

sqrt(5x) cannot simplify to x*sqrt5 because the x variable is not squared.

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A handbag was purchased for Rs.280/- and sold for Rs.350/- calculate profit%
Llana [10]

Answer:

profit is 25%

Step-by-step explanation:

profit%=sp-cp/cp×100%

=350-280/280×100%

=0.25×100

=25%

7 0
3 years ago
Which best describes a transformation that preserves the size, shape, and angles of an object? A. congruent transformation B. no
Harrizon [31]

Answer:

Your answer would be D: isometry

Step-by-step explanation:


6 0
3 years ago
Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
In-s [12.5K]

Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}

\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac

y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D

\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D

4 0
2 years ago
6. Which pair of points forms a vertical line segment that is 4 units long? (1 point) • (–3, 5) and (–7, 5) • (3, –8) and (3, –4
Ilia_Sergeevich [38]
(-7,5) and (-3,5) :) 
4 0
2 years ago
Read 2 more answers
The gray area is the sidewalk. the area of the sidewalk is ___________ square units.
Bas_tet [7]
The area of the sidewalk is 72 square units.                                                          Solution: First, multiply 10 by 12 which equals 120. Then, subtract 6x8=48. So, therefore, 120-48= 72
5 0
3 years ago
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