For there to be a region bounded by the two parabolas, you first need to find some conditions on
. The two parabolas must intersect each other twice, so you need two solutions to
You have
which means you only need to require that
. With that, the area of any such bounded region would be given by the integral
since
for all
. Now,
by symmetry across the y-axis. Integrating yields
![=4\left[c^2x-\dfrac{16}3x^3\right]_{x=0}^{x=|c|/4}](https://tex.z-dn.net/?f=%3D4%5Cleft%5Bc%5E2x-%5Cdfrac%7B16%7D3x%5E3%5Cright%5D_%7Bx%3D0%7D%5E%7Bx%3D%7Cc%7C%2F4%7D)
Since
, you have
.
<h2>YOUR ANSWER IS IN THE ATTACHMENT PLZZ REFER TO THE ATTACHMENT </h2><h2>MARK ME BRAINLIEST AND FOLLOW ME </h2>
Answer:22.383
Step-by-step explanation:
Divide 67.14 from 3
I think what you meant to type is "markup". If the markup is 6.5%, we need to increase the cost by that amount. To find 6.5% of a number we convert it to a decimal, .065, and we add 1.00, to get 1.065. The 1, when multiplied, gives us the original amount, and the .065 gives us the additional amount. We multiply that by 784.5. 784.5 x 1.065 = 835.49. The other way to do it is to just multiply by 0.065, and you get 784.5 x 0.065 = 50.99, then add it to the original amount, 784.5 + 50.99 = 835.49.
Answer:
(5,5)
Step-by-step explanation:
