120 / 18 = 20/3
x^3 / xy = x^2 / y
20x^2 / 3y
Answer:
AAS
Step-by-step explanation:
HEHE
9514 1404 393
Answer:
180 units
Step-by-step explanation:
The perimeter of ∆XYV is ...
Pxyv = XY +YV +VX
Pxyv = 29 +31 +40 = 100
The triangles are similar, so the scale factor from ∆XYV to ∆XZW applies to the perimeter. That scale factor is ...
WX/VX = (32+40)/40 = 1.8
Then ...
Pxzw = 1.8 × Pxyv = 1.8 × 100
Pxzw = 180 . . . units
Given:
P: (2,0,5)
L: (0,6,4)+t(7,-1,5)
and required plane, Π , passes through P and perpendicular to L.
The direction vector of L is V=<7,-1,5>.
For Π to be perpendicular to V, Π has V as the normal vector.
The equation of a plane with normal vector <7,-1,5> passing through a given point P(xp,yp,zp) is
7(x-xp)-1(y-yp)+5(z-zp)=0
Thus the equation of plane Π passing through P(2,0,5) is
7(x-2)-y+5(z-5)=0
or alternatively,
7x-y+5z = 14+25
7x-y+5z = 39
It's the second one hope this helped
