Answer:
Step-by-step explanation:
1022
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
Well first find the area of the semi-circle.
If the area of a cricle is equal to pi*radius^2 , then you can just find that and divide by 2.
So, A = pi*2^2. = 4pi
We know that the radius is 2 because the length of the side of the rectangle is 4, meaning that the diameter of the semi-circle is 4, and so the radius is 2 as it is half of the diameter.
We can easily calculate the area of the rectangle, which is
Length * width = 6*4 = 24.
Next we divide 4pi by 2 in order to get the area of the semi-circle, giving us an area of 2pi
We can just subtract 2pi from 24 and get the area of the shaded region.
Area of the shaded region (answer): 17.7
Answer:
(9g - 6f)(9g + 6f)
Step-by-step explanation:
81g^2 - 36f^2 =
(9g)² - (6f)² =
(9g - 6f)(9g + 6f)
