The first point on #14 is wrong, te coordinate is (1,0)
Slope for #14 is 2/2 or just 1
Yes, in the sense that the new area could be written as (x+1)^2 / 1.
Usually we would not bother with the "1" as divisor.
Let's actually do the work: what is the area of the square if we increase the side length of the existing square by 1 ft?
(x+1)^2 = x^2 + 2x + 1 (This is not a fraction, and thus not the ratio of
two integers, which, in turn, is the definition of
"rational number."
Answer:
We need to find the lowest common divisor which is the smallest possible number that is dividable by ALL numbers.
We have the following numbers:




For the denominators (3, 3, 5, 5) the least common multiple (LCM) is 15.
LCM(3, 3, 5, 5)
. Therefore, the least common denominator (LCD) is 15.
Rewriting the original inputs as equivalent fractions with the LCD:
125/15, 300/15, 75/15, 180/15
The diagonal WY bisects the diagonal XV at point D, which means that XV is divided into two equal line segments XD and XV.

Replace the equation above with the given expressions for both line segments:
XD= 2x-6
XV= 3x-6

Answer with Step-by-step explanation:
We are given that
a.



b.Radius=2.58 cm
Substitute the values in the formula and 

Hence, the area of circle =20.9 square cm
c.Area of circle=1530 square cm

Hence, the radius of circle=22.07 cm
c.Area of circle of radius 15.2 cm=
Area of circle of radius 15.1 cm=

Hence, the area of circle whose radius is 15.2 cm is greater than the area of circle of radius 15.1 cm by 9.52 square cm .