Ask question

Ask question

All categories

3 years ago

13

A bowling alley charges a rental fee of $12 for the lane. They then charge $7.75 for each game bowled. If I have a total of $105

. Write an inequality and solve it to find the maximum number of games, g, that I could play?

2 answers:

Xelga [282]3 years ago

7 0

Answer:

12

Step-by-step explanation:

12 + 7.75*g <= 105 Subtract 12

7.75g < =105 - 12 divide by 7.75

g <= 93 / 7.75

g < = 12

You have to put an equal sign in there because 7.75 divides equally into 93.

lana [24]3 years ago

5 0

The answer is 12 and i don’t want to do the step by step

You might be interested in

I need help 3/2x-5=7

Leviafan [203]

The answer to that is x=8

5 0

3 years ago

The length of a square is 256m and the breadth is 238m what is the perimeter

nikitadnepr [17]

The perimeter is 988 meters

Further explanation:

The given square has different length and breadth which means that the given square is a rectangle.

The formula for perimeter of a rectangle is:

$P=2L+2W$

Given

Length=L=256m

Breadth=W=238m

Putting the values in the formula:

$P=2(256)+2(238)\\=512+476\\=988\ meters$

The perimeter is 988 meters.

Keywords: Rectangle, Perimeter

Learn more about perimeter at:

#LearnwithBrainly

8 0

3 years ago

Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =

DanielleElmas [232]

Answer:

$c = 5$

Step-by-step explanation:

Given

$f(c) = M$

$f(x) = x^2 - x + 1$

$Interval: [1,8]$

$M = 21$

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

$f(x) = x^2 - x + 1$

$f(1) = 1^2 - 1 + 1$

$f(1) = 1$

$f(x) = 8^2 - 8 + 1$

$f(x) = 57$

$1 \le M \le 57$

$1 \le 21 \le 57$

M is within range.

Solving further:

We have:

$f(c) = f(x) = M$

$f(x) = 21$

Substitute 21 for f(x) in $f(x) = x^2 - x + 1$

$21 = x^2 - x + 1$

Express as quadratic function

$x^2 - x + 1 - 21 = 0$

$x^2 - x - 20 = 0$

Expand

$x^2 + 4x - 5x - 20$

$x(x+4)-5(x+4)=0$

$(x - 5)(x+4) = 0$

$x - 5 = 0$ or $x + 4= 0$

$x = 5$ or $x = -4$

The value of $x = -4$ is outside the $Interval: [1,8]$

So:

$x = 5$

$f(c) = f(x) = M$

$f(c) = f(5) = 21$

By comparison:

$c = 5$

4 0

3 years ago

PLEASE HELP ASAP!!

Elza [17]

Answer:

The parabolic equation does not intersect the linear equation.

Explanation:

Given equation's:

y = x² − 5x + 9
y = -2x

To solve , use substitution method by inserting 2nd equation into 1st

$\sf y = x^2 - 5x + 9$

when substituted y = -2x

$\sf -2x = x^2 - 5x + 9$

collect terms

$\sf x^2 - 5x+ 2x + 9=0$

simplify

$\sf x^2 - 3x + 9=0$

Find discriminant:

$\sf b^2 - 4ac$

$\sf (-3)^2 - 4(1)(9)$

$\sf -27$

As the discriminant is negative, it tell us that they both does not intersect each other.

7 0

1 year ago

Help. Calculus question.

elixir [45]

Answer:

64π/5 cubic units.

Step-by-step explanation:

The line x = 2 and y = x^3 intersect at the point (2 , 2^3) = (2, 8).

The required volume = volume of the cylinder with height 8 and radius 2 - the volume of shape form between the curve and the y axis when revolved about the y-axis.

Using the disk method for volumes of revolution:

Note that x = y^1/3 so:

the second volume = Integral π ((y^1/3)^2) dy between y = 0 and y = 8.

= 3/5 y^5/3 * π between 0 and 8

= 96π/5.

The required volume = π 2^2 *8 - 96π/5

= 32π - 96π/5

= 64π/5.

4 0

3 years ago