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3 years ago

How do I solve this radical and then check all the solutions?

Mathematics

1 answer:

MArishka [77]3 years ago

3 0

Answer:

This problem of equations involving surds can be solved by :

Firstly,square both sides of the equation to do away with the surd

(√x+3)²=(x-3)²

Next,we do away with the surd or let me put it as sign of square root and FOIL out the RHS

x+3=x²-6x+9

Rearranging leads to:

x²-6x-x+9-3=0

x²-7x+6=0 which factorises to:

(x-6)(x-1)=0

Finding the zeros leads to

x=6 or 1

We now conduct a test to see which value(s) of x satisfy the equation

√6+3=6-3

√9=3

3=3, so x=6 is true

Now for 1,

√1+3=1-3

√4 is not equal to -2

Therefore we conclude that x=6

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suter [353]

The answer is 29/34 your answer

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3 years ago

Shobos mother present age is six times shobos present age. Shobos age five from now will be one third of his mother's present ag

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equations:

$M = 6S$

$S + 5 = \frac{1}{3}M$

where $S$ is the current age of Shobos and $M$ is the current age of his mother.

Substituting the first equation into the second will allow us to solve for $S$ :

$S + 5 = \frac{1}{3}M$

$S + 5 = \frac{1}{3}(6S)$

$S + 5 = 2S$

$S = 5$

Substituting this value into the first equation gives us the age of the mother:

$M = 6S$

$M = 6(5)$

$M = 30$

5 0

3 years ago

Read 2 more answers

HELP IVE BEEN STUCK ON THIS FOREVER

jeyben [28]

Step-by-step explanation:

the figure I've circled is similar to yhe figure shown because when we compare the measurements of the length and breadth of both rectangles, we can see that both the rectangles have the see me measurements, 3ft and 7ft. The only difference however, is that the figures have been rotated differently, the figure shown is kept vertically, on the other hand, the figure I've circled is rotated horizontally.

hope that helps...

5 0

2 years ago

Two students, Ann and Max, factored the trinomial 4x2-6x -4. Ann factored it as 2(k 2xx+ 1) and Max factored it as (-2)4x+2), In

marishachu [46]

Given trinomial 4x^2-6x-4.

In order to factor a trinomial, we need to factor out greatest common factor (GCF).

In the given trinomial, we have terms 4x^2, -6x, -4.

We can see that all terms can be divided by a greatest number 2.

Therefore, greatest common factor would be 2 there.

We need to factor out 2 first.

On factoring out 2, we get

2(2x^2 -3x -2).

Now, we need to factor out trinomial 2x^2 -3x -2 now.

We can factor a trinomial by applying product sum rule.

We have a=2,b=-3,c=-2.

ac= 2*-2 = -4 and b=-3.

So, we need to find the factors of -4 that add upto -3.

Factors of -4 would be -4 and 1.

Let us replace -3x by -4x +1x in 2x^2 -3x -2 trinomial

2x^2 -3x -2 could be rewrite as 2x^2 -4x +1x -2.

Making it into two groups and factoring out GCF of each group.

We get

(2x^2 -4x) +(1x - 2)

2x(x-2) +1(x-2)

=(x-2)(2x+1)

Therefore, final factors of the trinomial is 2(x-2)(2x+1).

So, Ann factored form 2(x-2)(2x+1) is correct.

8 0

3 years ago

Could someone please help me asap? Thanks in advance! :)

Elden [556K]

Answer:

Step-by-step explanation:

the standard form of a quadratic equation is

ax² + bx + c = 0 : a ≠ 0

obtain (5 + x)(5 - x) = 7 in this form by expanding the factors

25 - x ² = 7 ( subtract 7 from both sides )

18 - x² = 0 ( multiply through by - 1 )

x² - 18 = 0 ← in standard form

with a = 1, b= 0 and c = - 18 → A

4 0

3 years ago