Using the z-distribution, a sample size of 180 is needed for the estimate.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
The margin of error is given by:
In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 98% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 2.327.
The population standard deviation is of 
, and to find the sample size, we have to solve for n when M = 4.
Hence:
n = 179.03.
Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.
More can be learned about the z-distribution at brainly.com/question/25890103
#SPJ1
The answer is A supplementary Angle
Answer:B
Step-by-step explanation:
3.1x10^9 is putting 9 zero’s behind the 3.1
move the decimal point over 9 spaces which will leave you with 3,100,000,000
= 3.1 Billion
<span>Let x=smaller number
Then x+5=larger number
Now we are told the following:
1/5(x+x+5)=x-5 multiply each side by 5
x+x+5=5x-25 subtract 5x and also 5 from both sides
x+x+5-5-5x=5x-5x-25-5 collect like terms
</span><span>-3x=-30 divide both sides by -3
x=10 smaller number
x+5=10+5=15 larger number
CK
1/5(10+15)=10-5
1/5(25)=10-5
5=5 </span>
Answer:
92
Step-by-step explanation:
Given
2n + t² ← substitute n = - 4 and t = - 10 into the expression
= 2(- 4) + (- 10)² = - 8 + 100 = 92
