The margin of error of this poll is
Given that 230 people were asked if they liked dogs, and 90% said they did.
In a random sample, a margin of error is a statistical measure that takes into account the discrepancy between actual and expected results.
Sample size (N)=230
Sample proportion
= 90% = 0.90 and
confidence interval = 99%
The critical value at 99% confidence interval with α=0.01 is

This value is taken from the Standard normal distribution table.
Now, we will calculate the margin of error (E) by using the formula

Substituting the values in the formula, we get

Hence, the margin of error when 230 people were asked if they liked dogs, and 90% said they did is 0.0507.
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Answer:
128 miligrams for 32 days
Step-by-step explanation:
To do this question, you first need to find out how much food she feeds per day so to do this, you do 12 mg/3 days and you get 4mg/day.
Then you multiply this number by 32.
4mg/day (32 days) = 128 mg
prob( it lands on open end) = 8/20 = 2/5
prob ( lands on closed end) = 4/20 = 1/5
The second choice is correct.
Since I can’t type the answer, here is the image of the answer. Hope I helped!
Answer:
I might be wrong so possibly DONT USE MY ANSWER but I think 30-33%