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3 years ago

Consider the angle 0. What is the value of the ratio opposite/adjacent

Mathematics

1 answer:

kykrilka [37]3 years ago

5 0

Answer:

Step-by-step explanation:

12/5

as a mixed fraction 2 2/5

or as decimal 2.4

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When Spencer was 5, he was 28 inches tall. Today he is 5 feet 3 inches tall. What is the percent increase in Spencer’s height?

Flura [38]

Answer:

The percentage increase in Spencer’s height is 125 %

Solution:

$\begin{array}{l}{\text { Percentage increase }=\frac{\text { change in height }}{\text { initial height }} \times 100 \%} \\\\ {\text { percentage increase }=\frac{\text { increased height - initial height }}{\text { initial height }} \times 100 \%}\end{array}$

Initial height of spencer = 28 inches

Increased height of spencer = 5 feet 3 inches

= 5 feet + 3 inches

(5 feet = 5 ×12=60 inches)

= 60 + 3

$\begin{array}{l}{\text { Increased height }=63 \text { inches }} \\ {\text { Percentage increase }=\frac{63-28}{28} \times 100 \%} \\\\ {=\frac{35}{28} \times 100 \%} \\\\ {=1.25 \times 100 \%} \\ {\text { percentage increase in height of spencer }=125 \%}\end{array}$

5 0

3 years ago

Solve for x. x³ = 216

iragen [17]

I got X = 6
If you replace x for 6 you should get 216

6^3 = 216

5 0

3 years ago

(5x+2)/8=x/6 what value will make it true??

Naya [18.7K]

X should equal -6/11 if I read the equation right

8 0

3 years ago

Read 2 more answers

Can someone help me<br> 7 + 2h = 3 + 4h

STALIN [3.7K]

h = 2

$7 + 2h = 3 + 4h$

You must isolate the variable to solve using the order of operations, or PEMDAS.

$4 = 2h$

Subtract 3 from both sides of the equation, and subtract 2h from both sides of the equation.

$\frac{4}{2} = h$

Divide both sides of the equation by 2.

$h = 2$

7 0

3 years ago

Ranch High School hosted a basketball tournament to raise money to update the school's gym. The cost for all the necessary suppl

Goryan [66]

Answer:

No.

Step-by-step explanation: Sadly the school will not have enough money to update the school. The amount of money they made was,$ 2,367.5 dollars. They would need $2367.5 more to update the school.

4 0

3 years ago