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Lelu [443]
3 years ago
8

Please I need help immediately ​

Mathematics
1 answer:
just olya [345]3 years ago
4 0

Answer:

Step-by-step explanation:

4x+6<= -54

4x <= -60

x <= -15    [The point -15 is included, so it must be a solid dot]

----------------

5x + 7 > -18

5x > -25

x > -5     [The point -5 is NOT included, so it should be an empty dot.]

Solution C seems the best.

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As I was going to St. Ives
cluponka [151]

Answer:

the answer should be 2,401 were going to St. Ives

Step-by-step explanation:

7 times 7 times 7 times 7 is 2401

4 0
3 years ago
Read 2 more answers
1.
ASHA 777 [7]

Answer:

Step-by-step explanation:

Vertex A of the triangle ABC when rotated by 90° counterclockwise about the origin,

Rule to be followed,

A(x, y) → P(-y, x)

Therefore, A(1, 1) → P(-1, 1)

Similarly, B(3, 2) → Q(-2, 3)

C(2, 5) → R(-5, 2)

Triangle given in second quadrant will be the triangle PQR.

If the point P of triangle PQR is reflected across a line y = x,

Rule to be followed,

P(x, y) → X(y, x)

P(-1, 1) → X(1, -1)

Similarly, Q(-2, 3) → Y(3, -2)

R(-5, 2) → Z(2, -5)

Therefore, triangle given in fourth quadrant is triangle XYZ.

6 0
3 years ago
ILL GIVE BRAINLIEST IF CORRECT!! The average of x+6, 6x+2, and 2x+7 is 4x-7. What is x?
mina [271]

Answer:

35/3

Step-by-step explanation:

\frac{x+6 + 6x+2+x+6}{3} =4x-7

Simplify to get

9x+14=3(4x-7)

35=3x

x=35/3 or 11.66

6 0
3 years ago
Help please someone i need help!!
ycow [4]

Answer:

c= 7

Step-by-step explanation:

6 0
2 years ago
I have the first part but I don't know how to do the second part<br><br> h e l p
Debora [2.8K]

\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42

3 0
3 years ago
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