Answer:
C- A proton has about the same mass as a neutron .
Explanation:
In an atom such as a carbon atom, the masses of the proton and neutrons are the same.
The mass of the electrons is very negligible.
- Protons are the positively charged particles in an atom
- Neutrons do not carry any charges
- Both protons and neutrons have similar masses.
- They contribute the bulk of the mass of the atom.
- The electrons carry negative charges and they have negligible masses.
The mass of protons and neutrons are similar.
Answer:
D. bromine
Explanation:
Highest electronegativity in the period has element closest to the *A group
K Ca Cu Br
<span>The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity. It can be calculated as follows:
P = density x g x h
P = 1000 kg/m^3 x 9.8 m / s x 33 ft x 0.3048 m/ft
P = 98572.32 kg/m^2
Hope this answers the question. Have a nice day.</span>
Answer:
166 torr
Explanation:
Let’s call ethane Component 1 and propane Component 2.
According to Raoult’s Law,
![p_{1} = \chi_{1}p_{1}^{\circ}\\p_{2} = \chi_{2}p_{2}^{\circ}](https://tex.z-dn.net/?f=p_%7B1%7D%20%3D%20%5Cchi_%7B1%7Dp_%7B1%7D%5E%7B%5Ccirc%7D%5C%5Cp_%7B2%7D%20%3D%20%5Cchi_%7B2%7Dp_%7B2%7D%5E%7B%5Ccirc%7D)
where
p₁ and p₂ are the vapour pressures of the components above the solution
χ₁ and χ₂ are the mole fractions of the components
p₁° and p₂° are the vapour pressures of the pure components.
Data:
p₁° = 304 torr
p₂° = 27 torr
n₁ = n₂
1. Calculate the mole fraction of each component
χ₁ = n₁/(n₁ + n₂)
χ₁ = n₁/n₁ + n₁)
χ₁ = n₁/(2n₁)
χ₁ = ½
χ₁ = 0.0.5
χ₂ = 1- χ₁ = 1- 0.5 = 0.5
2. Calculate the vapour pressure of the mixture
![p_{1} = 0.5 \times \text{304 torr} = \text{ 152 torr}\\p_{2} = 0.5 \times \text{27 torr} = \text{ 13.5 torr}\\p_{\text{tot}} = p_{1} + p_{2} = \text{152 torr + 13.5 torr} = \textbf{166 torr}](https://tex.z-dn.net/?f=p_%7B1%7D%20%3D%200.5%20%5Ctimes%20%5Ctext%7B304%20torr%7D%20%3D%20%5Ctext%7B%20152%20torr%7D%5C%5Cp_%7B2%7D%20%3D%200.5%20%5Ctimes%20%5Ctext%7B27%20torr%7D%20%3D%20%5Ctext%7B%2013.5%20torr%7D%5C%5Cp_%7B%5Ctext%7Btot%7D%7D%20%3D%20p_%7B1%7D%20%2B%20p_%7B2%7D%20%3D%20%5Ctext%7B152%20torr%20%2B%2013.5%20torr%7D%20%3D%20%5Ctextbf%7B166%20torr%7D)
![\text{The vapour pressure above the solution is $\boxed{\textbf{166 torr}}$}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20vapour%20pressure%20above%20the%20solution%20is%20%24%5Cboxed%7B%5Ctextbf%7B166%20torr%7D%7D%24%7D)
Answer:
1
Explanation:
The empirical formula describes the simplest whole number ratio of each type of atom in a compound. To find this formula, you need to (1) convert grams of each element to moles (via their atomic masses) and then (2) find the ratio of each element (by dividing each molar value by the smallest mole value).
(Step 1)
Atomic Mass (Zn): 65.380 g/mol
Atomic Mass (C): 12.011 g/mol
Atomic Mass (O): 15.998 g/mol
10.40 grams Zn 1 mole
------------------------ x ------------------------ = 0.159 moles Zn
65.380 grams
1.92 grams C 1 mole
--------------------- x ----------------------- = 0.160 moles C
12.011 grams
7.68 grams O 1 mole
---------------------- x ------------------------ = 0.480 moles O
15.998 grams
(Step 2)
0.159 moles Zn / 0.159 = 1 atom Zn
0.160 moles C / 0.159 = 1 atom C
0.480 moles O / 0.159 = 3 atom O
The empirical formula is Zn₁C₁O₃. Therefore, the value that should be in the space is 1.