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Andrew [12]
3 years ago
11

Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number. CaCO3(s) → CaO(s) + CO2(g) ΔGf,CaCO3 = −1,1

28.76 kJ/mol ΔGf,CaO = −604.17 kJ/mol ΔGf,CO2 = −394.4 kJ/mol
Chemistry
1 answer:
FrozenT [24]3 years ago
3 0

Answer: \Delta G_{rxn} for the given reaction is 130.19kJ/mol

Explanation:

To Calculate the \Delta G_{rxn}, we use the formula:

\Delta G_{rxn}=\Delta G_{products}-\Delta G_{reactants}

For the given chemical reaction:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

We are given:

\Delta G_{CaCO_3}=-1128.76kJ/mol\\\Delta G_{CaO}=-604.17kJ/mol\\\Delta G_{CO_2}=-394.4kJ/mol

Now, to calculate \Delta G_{rxn}, we put the values in the above equation:

\Delta G_{rxn}=(\Delta G_{CaO}+\Delta G_{CO_2})-\Delta G_{CaCO_3}

\Delta G_{reaction}=(-604.17-394.4)-(-1128.76)kJ/mol\\\Delta G_{reaction}=130.19kJ/mol

As, the value of \Delta G_{reaction} comes out to be positive, the reaction is said to be non-spontaneous reaction.

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