What is the symbol for the element sodium?

slamgirl [31]

Pumice rocks are formed due to the air that is trapped in between the rocks, a body of magma spurting out with dissolved gas under pressure. As the magma cracks through the Earth’s surface, the sudden pressure drop causes the gas to come out of the solution. The flash of gas form the vent slices the magma and blows it out as a molten lather. The lather hastily solidifies as it flies into the air and falls back to Earth as pieces of pumice.

7 0

3 years ago

A chemist adds 405.0mL of a 0.79M sodium carbonate solution to a reaction flask. Calculate the millimoles of sodium carbonate th

Sophie [7]

Answer:

320 mmol

Explanation:

405.0 mL * 1L/1000 mL = 0.4050 L

0.79 M = 0.79 mol/L

0.79 mol/L * 0.4050 L=0.32 mol

0.32 mol * 10^3 mmol/1 mol = 320 mmol

4 0

4 years ago

Give the name and formula of the compound formed from the following elements: a) Sodium and nitrogen b) Oxygen and strontium c)

elena-s [515]

Answer: a) Sodium and nitrogen : $NaN_3$ : sodium nitride.

b) Oxygen and strontium : $SrO$ : strontium oxide.

c) Aluminum and chlorine : $AlCl_3$ : aluminium chloride.

d) Cesium and bromine : $CsBr$ : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as $Na^{+}$ cation and nitrogen forms an anion $N^{3-}$ with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaN_3$ named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as $Sr^{+}$ cation and oxygen forms an anion $O^{2-}$ with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $SrO$ named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as $Al^{3+}$ cation and chlorine forms an anion $Cl^{-}$ with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $AlCl_3$ named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as $Cs^{+}$ cation and bromine forms an anion $Br^{-}$ with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $CsBr$ named as cesium bromide.

7 0

3 years ago

A balloon contains a fixed amount of helium. If the initial conditions are 1.12 liters, 3.00 atmospheres, and 19 degrees Celsius

Semmy [17]

Answer:

The final volume will be 3.39 liters

Explanation:

P1V1/T1 = P2V2/T2

P1 = 3 atm

T1 = 19( degrees celsius) + 273 = 292 K

V2 = TO BE DETERMINED

P2 =1 atm

T2 = 22( degrees celsius) + 273 = 295 k

P1V1/T1 = P2V2/T2

V2 = P1V1T2/P2T1 = (3)(1.12)(295)/(1)292) = 3.39 Liters

4 0

3 years ago

The pOH of a solution is

Volgvan

The pOH of a solution is the negative logarithm of the hydroxide-ion concentration.

4 0

3 years ago