C12H22O11 + 12O2 ---> 12CO2 + 11H2O

1 answer:

5 0

Molar mass sucrose ( C12H22O11 ) = 342 g/mol

8.0 g of O2 is the limiting factor of the reaction reagent

C12H22O11 + 12 O2 ------------> 12 CO2 + 11 H2O

1 mol C12H22O11 ------------- 342 g
x mol C12H22O11 ------------- 10 g

x = 10 / 342

x = 0,029 mol of sucrose

answer A

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