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allochka39001 [22]
3 years ago
9

7/12 plus 1/4 equal to 8/12 Does answer 3 make sense? Yes or no

Mathematics
2 answers:
MrRissso [65]3 years ago
4 0
Nope. It’s 10/12 or 5/6

To solve it, make both fractions have the same denominator (the bottom number). 7/12 can stay the same and we can multiply 1/4 by three to make it a fraction with the denominator as 12. It equals 3/12. Now add 7/12+3/12=10/12. We can simply it to 5/6 by dividing 10 and 12 by 2.
Assoli18 [71]3 years ago
3 0
No
7/12 + 1/4 = 10/12
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Svetllana [295]

Answer:

the second one iy s very incorrect

7 0
3 years ago
2/5 - 1/3 (simplified if possible)
Kipish [7]

Answer:

1/15

Step-by-step explanation:

(1).   <em>Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD (Least Common Denominator). </em>

So lets do step one now, the LCD is 15 so we have to make both denominators agree on one number, so 15 is the number both denominators agree on.

Solve:

2*3/5*3 - 1*5/3*5

(2). <em>Complete the multiplication.</em>

6/15 - 5/15

(3). <em>The two fractions now have like denominators so you can subtract the numerators.</em>

6 - 5 / 15 - 15 = 1/15

*Pro tip:

<em>The denominator doesn't change and stays the same. So you don't </em>

<em>subtract the 15 by 15.</em>

(4). <em>Then you'll get the answer and then if you can simplify then simplify.</em>

<em />

The Answer is 1/15, and cannot be simplified.

So the answer is 1/15

Hope this helps!

7 0
2 years ago
Please help and EXPLAIN !!!!!!! thank you!!! =)))
nataly862011 [7]

The change in profit from 3 days to 8 days = 74 - 59 = $15

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The answer is A. $3

5 0
3 years ago
Read 2 more answers
Please help with number 2 and 3
a_sh-v [17]
The question 2 .
428×7.1=3038.8
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3 0
4 years ago
The table shows the cost of different numbers of yards of the material that Marnie wants to buy. Marine needs 3 yards of the mat
valentinak56 [21]
It would cost $14.04. The equation for this would be y = 4.68x. If you multiply 3 by 4.68, you would get 14.04.
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3 years ago
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