The area of a regular hexagon with an apothem 18.5 inches long and a side 21 inches is 1, 165. 5 In²
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How to calculate the area of a regular hexagon</h3>
The formula is given thus;
Area of hexagon = (1/2) × a × P
where a = the length of the apothem
P = perimeter of the hexagon
Given a = 18. 5 inches
Note that Perimeter, p = 6a with 'a' as side
p = 6 × 21 = 126 inches
Substitute values into the formula
Area, A = 1 ÷2 × 18. 5 × 126 = 1 ÷2 × 2331 = 1, 165. 5 In²
Thus, the area of the regular hexagon is 1, 165. 5 In²
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Answer: This is how I would do it 8x67=402
Step-by-step explanation:
Answer:
m=6
Step-by-step explanation:
8(3+7m)=360
24 + 56m = 360
-24 -24
56m = 336
/56 /56
m = 6
Y = mx + b....m is the slope and b is the y intercept
slope(m) = 5...(4,0)...x = 4 and y = 0
now we sub our info into y = mx + b...we r looking for b, the y intercept
0 = 5(4) + b
0 = 20 + b
-20 = b
so ur equation is y = 20x - 20...but we need it in standard form
Ax + By = C
y = 20x - 20....subtract 20x from both sides
-20x + y = -20...multiply by -1 to make x positive
20x - y = 20 <== standard form
Here, first we need to calculate the slope of the line,
m = y2 - y1 / x2-x1
m = 6 + 2 / 3 -1
m = 8/ 2
m = 4
Now, Take first coordinate: y - 6 = 4 (x - 3)
Second coordinate: y + 2 = 4 (x - 1)
In short, Your Answers would be Option A & F
Hope this helps!