3 years ago

Quadrilateral ABCD is a rhombus. Given tha m

Mathematics

2 answers:

Tems11 [23]3 years ago

4 0

Answer:

m<EDA=35°

m<DAE=35 diagonal bisect it

Step-by-step explanation:

m<AED=180-2×35=110°(by sum of interior angle of the triangle)

m<BCE=mDAE=35° alternate angle

Vlad [161]3 years ago

4 0

<h3>Answer:</h3>

In quadrilateral ABCD i.e, rhombus

m∠AED = 180° - (35° + 35°)

180° - 70°
110°

m∠DAE = 35° (In rhombus, diagonal bisect each other)

m∠BCE = 35° (Alt. interior angle)

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