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pychu [463]
3 years ago
8

Quadrilateral ABCD is a rhombus. Given tha m

Mathematics
2 answers:
Tems11 [23]3 years ago
4 0

Answer:

m<EDA=35°

m<DAE=35 diagonal bisect it

Step-by-step explanation:

m<AED=180-2×35=110°(by sum of interior angle of the triangle)

m<BCE=mDAE=35° alternate angle

Vlad [161]3 years ago
4 0
<h3>Answer:</h3>

In quadrilateral ABCD i.e, rhombus

m∠AED = 180° - (35° + 35°)

  • 180° - 70°
  • 110°

m∠DAE = 35° (In rhombus, diagonal bisect each other)

m∠BCE = 35° (Alt. interior angle)

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kakasveta [241]

Answer:

A solution point is (2,2)

Step-by-step explanation:

Graph the lines. If it is just greater that or less than, use dashed lines. I fits greater than or equal too, or other symbols like that, use a solid line

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I am thinking of six different odd numbers, the mean of the numbers is 16, the median is 15, the range is 26, the greatest numbe
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Answer:

Step-by-step explanation:

information from the range

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