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kirill115 [55]
2 years ago
15

Fill in missing numbers. 12÷0.3=... ÷ 3

Mathematics
2 answers:
DiKsa [7]2 years ago
7 0
12 divided by 0.3 equals 40
snow_tiger [21]2 years ago
7 0

Answer:

120

Step-by-step explanation:

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Graph this function using intercepts: <br><br>4x - 5y = 40 ​
DochEvi [55]

use photomath for that that's way easier

4 0
3 years ago
Read 2 more answers
The parent function of the function g(x) = (x – h)2 + k is f(x) = x2. The vertex of the function g(x) is located
Katen [24]

9514 1404 393

Answer:

  (h, k) = (9, -8)

Step-by-step explanation:

The function g(x) is "vertex form" for a quadratic whose vertex is (h, k). We are told the vertex is (9, -8), so we have ...

  (h, k) = (9, -8) . . . . the values of h and k

7 0
3 years ago
What is 14x14x14 equal
N76 [4]
2744 is the answer. can be written as 14^3 just in case you need to know that.
8 0
3 years ago
Calculate the probability of flipping a coin 20 times and getting 4 heads. Round your answer to the nearest ten thousandth.
lorasvet [3.4K]

Answer:

0.0046

Step-by-step explanation:

5 0
3 years ago
PYTHAGOREAN THEOREM IN 3D URGENT PLEASE PHOTO INSERTED
Andrews [41]

To find the length of the diagonal, we need to calculate the length of the base first and then use the value to calculate the diagonal since we are given the value of height of the triangle.

<h3>Pythagorean Theorem</h3>

This theorem is used to find the missing side of a right angle triangle given that we have the length of two sides.

To calculate the base of the triangle, let's use Pythagorean theorem here

x^2 = y^2 + z^2\\x^2 = 2^2 + 3^2\\x^2 = 4 + 9 \\x^2 = 13\\x = \sqrt{13} \\x = 3.61

Having the length of the base, let's consider the height of the triangle which is 6 and substitute the values.

d^2 = 6^2 + 3.61^2\\d^2 = 36 + 13.0321\\d^2 = 49.0321\\d = \sqrt{49.0321} \\d = 7.00

From the calculations above, the values of the triangle are

  • diagonal = 7
  • base = 3.61
  • height = 6

Learn more on pythagorean theorem here;

brainly.com/question/231802

#SPJ1

7 0
1 year ago
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