Step-by-step explanation:
write a formula that models this.
9.30x = money earned
If he works 2 hours, he'll get $9.30 times (2)
and so on. so you write and solve
9.30(1), 9.30(5), 9.30(8)
for the second part you want to substitute 180 for the amount earned which will become
9.30x = 180 then you solve for x
Answer:
3600 ways
Step-by-step explanation:
person A has 7 places to choose from :
→ He has 2 places ,one to the extreme left of the line ,the other to the extreme right of the line
If he chose one of those two ,person B will have 5 choices and the other 5 persons will have 5! Choices.
⇒ number of arrangements = 2×5×5! = 1 200
→ But Person A also , can choose one of the 5 places in between the two extremes .
If he chose one of those 5 ,person B will have 4 choices and the other 5 persons wil have 5! Choices.
⇒ number of arrangements = 5×4×5! = 2 400
In Total they can be arranged in :
1200 + 2400 = 3600 ways
Answer:
True
Step-by-step explanation:
The equation of direct variation is
y = kx ← k is the constant of variation
To find k divide both sides by x
= k
That is the constant is the ratio of y- values to x- values
Answer:
look below bestie
Step-by-step explanation:
ok so i dont know most of it (sryy) but the area of the entire pizza is 535.84in², the radius of the pizza is about 13.05 and yea. thats all i got
Answer:
if repetition is allowed,
if repetition is not allowed.
Step-by-step explanation:
For the first case, we have a choice of 26 letters <em>each step of the way. </em>For each of the 26 letters we can pick for the first slot, we can pick 26 for the second, and for each of <em>those</em> 26, we can pick between 26 again for our third slot, and well, you get the idea. Each step, we're multiplying the number of possible passwords by 26, so for a four-letter password, that comes out to 26 × 26 × 26 × 26 =
possible passwords.
If repetition is <em>not </em>allowed, we're slowly going to deplete our supply of letters. We still get 26 to choose from for the first letter, but once we've picked it, we only have 25 for the second. Once we pick the second, we only have 24 for the third, and so on for the fourth. This gives us instead a pretty generous choice of 26 × 25 × 24 × 23 passwords.