Answer:
10 ways
Step-by-step explanation:
The number of ways in which five basketball players could be placed in three positions is:
5
= 
= 
= 
= 5 × 2
= 10
The basketball players can be arranged in 10 ways.
it is C. i think because this i looked it up trust me
<h3>Answer: 10</h3>
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Explanation:
We'll start off converting each mixed number into an improper fraction.
The formula to use is 
So,

And,

So the task of computing
is exactly the same as computing 
Notice how we have an 8 up top and an 8 down below. Those 8's cancel out and we're left with
. That fraction does not reduce any further.
The last step is to convert that improper fraction result to a mixed number.

Or you could note that 17/3 leads to 5 remainder 2. The 5 is the whole part and the 2 forms the numerator of the fractional part 2/3.
The value is in
form where
Therefore, A+b+c = 5+2+3 = 10
-3,-7.5,2 2/3 are the opposites of those numbers