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2 years ago

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An axiom in educlidean geometry states that in space there are at least points that do

1 answer:

ICE Princess25 [194]2 years ago

7 0

Answer:

a point is the answer sus

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The quotient of a number and five is eleven. Find the number

alexandr1967 [171]

Answer:

x=55

Step-by-step explanation:

x/5=11

11x5=55

x=55

5 0

3 years ago

Read 2 more answers

A baby weighs 7 pounds at birth. the table shows the baby's weigh after each month of its birth, up to the sixth month

Alexus [3.1K]

What’s the question?

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2 years ago

Help me plss need help with theses three

fiasKO [112]

interior angle of a regular 18-gon.
It is easier to calculate the exterior angle of a regular polygon of n-sides (n-gon) by the relation
exterior angle = 360/n
For a 18-gon, n=18, so exterior angle = 360/18=20 °
The value of each interior angle is therefore the supplement, or
Interior angle = 180-20=160 degrees.

Naming of a 9-gon
A polygon with 9 vertices is called a nonagon (in English) or enneagon (French ennéagone, but the English version is sometimes used)
You had a good start with the correct answer.

Exterior angle of a 15-gon
The exterior angle of a 15-gon can be calculated using the relation given in the first paragraph, namely
Exterior angle = 360/15=24 degrees

4 0

3 years ago

Just help please need to pass

Anni [7]

Answer: $\frac{1}{10}$

Step-by-step explanation:

First, we need to find the common denominator

The easiest way to do this is by multiplying the two given denominators, which are 2 and 5.

2 × 5 = 10

So, our common denominator is 10. Then, multiply the numerators of the two fractions by 2 and 5. Here's why:

$\frac{3*2}{5*2}$ = $\frac{6}{10}$ We multiplied the top and bottom by 2 to make sure our new fraction stays equivalent to the original fraction.

Do the same thing for the other one:

$\frac{1*5}{2*5}$ = $\frac{5}{10}$

Finally, subtract the two fractions to find the difference between the two times:

$\frac{6}{10} -\frac{5}{10}$ = $\frac{1}{10}$

The reason we used the common denominator is because we can only add or subtract fractions if they have the same denominator.

7 0

3 years ago

Read 2 more answers

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago