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Dmitry_Shevchenko [17]

2 years ago

13

Anna has twice as many video games as Kyle. Maurice has 5 more video games than Anna. The total number of video games is less th

an 40. Write and solve an inequality to determine the greatest number of video games Maurice could have.

2 answers:

Katyanochek1 [597]2 years ago

7 0

17 is the answer. Yes

NNADVOKAT [17]2 years ago

5 0

Answer:

She has 17 video games. (Possible answer.) Hope this helps!

Step-by-step explanation:

$2x+5$

-5. -5

$2x$

2. 2

$X$

or 17 since it is less than 17.2

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This isn't a major question but does anyone know how a zero would affect a 98% A.

lubasha [3.4K]

Answer:

it would drag your grade down to a B

Step-by-step explanation:

3 0

3 years ago

A 4 foot tree was planted in 2012 outside a high school. The tree grew continuously by 22% each year from that point. Find out w

Brut [27]

Answer:

The height of the tree in 2020 was of 19.63 feet.

Step-by-step explanation:

Exponential equation for growth:

The exponential equation for the growth of an amount has the following format:

$H(t) = H(0)(1+r)^t$

In which H(t) is the amount after t years, H(0) is the initial amount and r is the growth rate, as a decimal.

A 4 foot tree was planted in 2012 outside a high school.

This means that $H(0) = 4$

The tree grew continuously by 22% each year from that point.

This means that $r = 0.22$

Find out what the height of the tree was in 2020.

2020 is 2020 - 2012 = 8 years after 2012, so this is H(8).

$H(t) = H(0)(1+r)^t$

$H(t) = 4(1+0.22)^t$

$H(4) = 4(1.22)^t$

$H(4) = 4(1.22)^8 = 19.63$

The height of the tree in 2020 was of 19.63 feet.

6 0

3 years ago

Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

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3 years ago

Write the following proportion using colons. 7 is to 21 as 3 is to 9.

eduard

This is how proportion is written 7:21=3:9. The colons are sign of division so it can be shown in the terms of fraction as 7/21=3/9 or 1/3=1/3

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3 years ago

What is the solution to the equation 93x ≈ 7?

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X= 7/93 or roughly 0.07526...

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3 years ago