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Masja [62]
3 years ago
11

Identify each of A , B and C as an outlier , gap , or cluster

Mathematics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:I need to see images in order to answer:/

Step-by-step explanation:

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Some conveyor belts have two pulleys. If one pulley has a diameter of 45 cm and another has a diameter of 20 cm, what is the rat
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20:45 or 4:9 if simplified
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The table below shows the number of cameras made when an assembly line runs at a constant rate for a certain number of hours. Nu
jeka57 [31]

Computing the rate we get:

\frac{300}{10}\frac{cameras}{\text{hour}}=30\frac{cameras}{\text{hour}}

Then, when the assembly line runs at the same rate for 24 hours they will produce:

24\text{hour}\cdot30\frac{cameras}{\text{hour}}=720\text{ cameras}

Answer: Option C) 720.

7 0
1 year ago
What is the square root of -1?<br>-i<br>I<br>-1<br>1​
vova2212 [387]

Answer:

square root(-1) =  i

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Soni rent Anju a sum of Rs 40,000 at the rate of 2 paisa per 2 rupees per
galben [10]

Answer:

RS 14400

Step-by-step explanation:

Given the following :

Principal sum = RS 40000

Rate = 2 paisa per 2 rupee per month

Interest at the end of 3 years

1 rupee = 100 paisa

2 Paisa per 2 rupee per month :

2/200 per month = 1 / 100 per month,

Hence rate = 0.01 = 1% monthly

Annual rate = 1% × 12 = 12 % = 0.12

Simple interest :

Principal × rate × time

40000 × 0.12 × 3

40000 × 0.36

= RS 14,400

3 0
3 years ago
For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0
2 years ago
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