Let s=number of seeds and t=number of days...
st=120 and (s+10)(t-2)=120
From the first we can say t=120/s, now using this value of t in the second equation gives us:
(s+10)(120/s-2)=120
(s+10)(120-2s)/s=120
(s+10)(120-2s)=120s
120s-2s^2+1200-20s=120s
2s^2+20s-1200=0
s^2+10s-600=0
(s+30)(s-20)=0, since s>0
s=20, and since she planted s+10 seeds per day to finish two days earlier:
20+10=30
She planted 30 seeds per day.
Answer:
see below
Step-by-step explanation:
1.)
(0, 4)
(1, 7)

y = 3x + b
(4) = 3(0) + b
b = 4
y = 3x + 4
Rate of change: 3 initial value: 4
2.)
(0, -5)
(1, -3)

y = 2x + b
(-5) = 2(0) + b
b = -5
Rate of change: 2 initial value: -5
Solution :
Let
and
represents the proportions of the seeds which germinate among the seeds planted in the soil containing
and
mushroom compost by weight respectively.
To test the null hypothesis
against the alternate hypothesis
.
Let
denotes the respective sample proportions and the
represents the sample size respectively.




The test statistic can be written as :

which under
follows the standard normal distribution.
We reject
at
level of significance, if the P-value
or if 
Now, the value of the test statistics = -1.368928
The critical value = 
P-value = 

= 0.171335
Since the p-value > 0.05 and
, so we fail to reject
at
level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the
of the seeds that
with the percent of the
in the soil.
Answer:
126,720 inches
Step-by-step explanation: