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Elis [28]
3 years ago
14

Four students are asked to draw a parallelgram. each drew a differently-named figure

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0
So basicly the question is asking, name 4 parrelegrams. Thr answer will be, Rectangle, Squrare Trapizoid, and Rhymbus. Not is a specifc order.
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Solve the differential equation y prime equals the product of 2 times x and the square root of the quantity 1 minus y squared .
MatroZZZ [7]

Answer:

1. y = sin(x²+C)

2. see below

Step-by-step explanation:

1. \frac{dy}{dx} = 2x\sqrt{1-y^2}

separation of variables

\frac{dy}{\sqrt{1-y^2} } = 2xdx

integration both sides\int\frac{dy}{\sqrt{1-y^2} } = \int2xdx

you should get :

sin^{-1} (y) = x^2+C remember constant of integration!!

2. y = sin(x²+C)

3 = sin(0+C)

y(0) = 3 does not have a solution because our sin graph is not shifted vertically or multiplied by a factor whose absolute value is greater than 1, so our range is [-1,1] and 3 is not part of this range

4 0
3 years ago
As the teams fundraiser,Agnes and Betty both sold candy bars at the end of the fundraiser Agnes determined that she sold 8 more
Romashka-Z-Leto [24]

Answer:

356

Step-by-step explanation:

5 0
2 years ago
(Please answer soon as possible) At the beginning of the day the stock market goes up 60 3/4 points and stays at this level for
Svet_ta [14]

Answer:

it is 2766628276262626828373636737 points

Step-by-step explanation:

no explanation needed lol

3 0
3 years ago
Read 2 more answers
the product of two whole numbers is 36 . what is the greatest possible sum that the number can have?​
ch4aika [34]

Whole numbers are positive numbers without decimals.  First, list all the whole number factors of 36:

1 and 36

2 and 18

3 and 12

4 and 9

6 and 6

Next, see which one of those pairs has the highest sum:

1+36=37

2+18=20

3+12=15

4+9=13

6+6=12

The greatest possible sum the numbers can have is 37.

Hope this helps!!

3 0
2 years ago
A. 55<br> b. 70<br> c. 110<br> d. 125
morpeh [17]

Answer:

b

Step-by-step explanation:

7 0
2 years ago
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