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Lapatulllka [165]
2 years ago
11

A block of metal with volume 15 m3 and density 8,800 kg/m3 is combined with another metal of mass 850 kg and volume 6.2 m3 to fo

rm an alloy.
What is the density of the alloy to the nearest integer?
Mathematics
2 answers:
boyakko [2]2 years ago
4 0

Answer:

El aluminio es un metal ligero con una densidad de 2.70 g/cm3, y por ello, aunque las aleaciones de aluminio tienen características mecánicas relativamente bajas comparadas con las del acero, su relación resistencia-peso es excelente. Es precisamente debido a esto que el aluminio se utiliza cuando el peso es un factor importante, como ocurre en las aplicaciones aeronáuticas y de automoción.

 

Tabla 13.8. Propiedades mecánicas y aplicaciones de algunas aleaciones comerciales de aluminio.

El aluminio también responde fácilmente a los diferentes mecanismos de endurecimiento, tal como se recoge en la tabla 13.8, donde se observa que el mecanismo más notable es el de endurecimiento por precipitación, donde se consigue una dureza hasta 30 veces superior a la del aluminio puro.

Por otra parte, el aluminio no suele presentar un límite de resistencia a la fatiga bien definido, de modo que la fractura puede suceder incluso a niveles muy bajos. Debido a su bajo punto de fusión, el aluminio no se comporta bien a temperaturas elevadas. Finalmente, las aleaciones de aluminio tienen escasa dureza, lo que origina poca resistencia al desgaste abrasivo en ocasiones.

-BARSIC- [3]2 years ago
3 0

Answer:

Aluminum is a light metal with a density of 2.70 g / cm3, and therefore, although aluminum alloys have relatively low mechanical characteristics compared to steel, their strength-to-weight ratio is excellent. It is precisely because of this that aluminum is used when weight is an important factor, as in aeronautical and automotive applications.

 

Table 13.8. Mechanical properties and applications of some commercial aluminum alloys.

Aluminum also responds easily to the different hardening mechanisms, as shown in table 13.8, where it is observed that the most notable mechanism is that of hardening by precipitation, where a hardness of up to 30 times higher than that of pure aluminum is achieved. .

On the other hand, aluminum does not usually have a well-defined limit of resistance to fatigue, so that fracture can occur even at very low levels. Due to its low melting point, aluminum does not perform well at elevated temperatures. Finally, aluminum alloys have low hardness, resulting in poor resistance to abrasive wear at times.

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She made a mistake in steps 3-4
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Are the expressions 3/4a + 8 - 1/4a - 2 and 1/2(a + 12) equivalent? Show why or why not.
natta225 [31]

Answer:Yes they are equivalent.

Step-by-step explanation:

3/4a + 8 - 1/4a - 2 1/2(a + 12)

Combine like terms Distributive property

2/4a+6 1/2a+6

2/4=1/2 (simplify)

1/2+6=1/2+6

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3 years ago
The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det
Maru [420]

Answer:

0.077994

Step-by-step explanation:

Given that the owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club.

H_0: Mean = 30\\H_a: Mean >30

(Right tailed test)

Sample size = n=250

Sample mean = 30.45

Mean difference =30.45-30=0.45\\

Sample std dev s = 5

Sample std error = \frac{5}{\sqrt{n} } =\frac{5}{\sqrt{250} } \\=0.3163

Test statistic = Mean diff/std error = =\frac{0.45}{0.3163} =1.423

Since population std deviation is not know we use t test

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4 0
3 years ago
Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0
2 years ago
Use the functions f(x) = 4x² + 3 and g(x) = 3x + 2 to evaluate the following.
natita [175]

Answer:

Step-by-step explanation:

f(-2)= 4(-2)^2 + 3 = 4(4) + 3 = 16 + 3 = 19

g(19) = 3(19) + 2 = 57 + 2 = 59

g(-2)= 3(-2) + 2 = -6 + 2 = -4

f(-4)= 4(-4)^2 + 3 = 64 + 3 = 67

7 0
2 years ago
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