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Lapatulllka [165]
3 years ago
11

A block of metal with volume 15 m3 and density 8,800 kg/m3 is combined with another metal of mass 850 kg and volume 6.2 m3 to fo

rm an alloy.
What is the density of the alloy to the nearest integer?
Mathematics
2 answers:
boyakko [2]3 years ago
4 0

Answer:

El aluminio es un metal ligero con una densidad de 2.70 g/cm3, y por ello, aunque las aleaciones de aluminio tienen características mecánicas relativamente bajas comparadas con las del acero, su relación resistencia-peso es excelente. Es precisamente debido a esto que el aluminio se utiliza cuando el peso es un factor importante, como ocurre en las aplicaciones aeronáuticas y de automoción.

 

Tabla 13.8. Propiedades mecánicas y aplicaciones de algunas aleaciones comerciales de aluminio.

El aluminio también responde fácilmente a los diferentes mecanismos de endurecimiento, tal como se recoge en la tabla 13.8, donde se observa que el mecanismo más notable es el de endurecimiento por precipitación, donde se consigue una dureza hasta 30 veces superior a la del aluminio puro.

Por otra parte, el aluminio no suele presentar un límite de resistencia a la fatiga bien definido, de modo que la fractura puede suceder incluso a niveles muy bajos. Debido a su bajo punto de fusión, el aluminio no se comporta bien a temperaturas elevadas. Finalmente, las aleaciones de aluminio tienen escasa dureza, lo que origina poca resistencia al desgaste abrasivo en ocasiones.

-BARSIC- [3]3 years ago
3 0

Answer:

Aluminum is a light metal with a density of 2.70 g / cm3, and therefore, although aluminum alloys have relatively low mechanical characteristics compared to steel, their strength-to-weight ratio is excellent. It is precisely because of this that aluminum is used when weight is an important factor, as in aeronautical and automotive applications.

 

Table 13.8. Mechanical properties and applications of some commercial aluminum alloys.

Aluminum also responds easily to the different hardening mechanisms, as shown in table 13.8, where it is observed that the most notable mechanism is that of hardening by precipitation, where a hardness of up to 30 times higher than that of pure aluminum is achieved. .

On the other hand, aluminum does not usually have a well-defined limit of resistance to fatigue, so that fracture can occur even at very low levels. Due to its low melting point, aluminum does not perform well at elevated temperatures. Finally, aluminum alloys have low hardness, resulting in poor resistance to abrasive wear at times.

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The completely factored form of f(x) = 6x³ - 13x² - 4x + 15 is f(x) = (x + 1)(2x - 3)(3x - 5)

<h3>How to factor the expression?</h3>

The expression is given as:

f(x) = 6x³ - 13x² - 4x + 15

Expand the expression

f(x) = 6x³ - 19x² + 6x² + 15x - 19x + 15

Rewrite as:

f(x) = 6x³ + 6x² + 15x- 19x²   - 19x + 15

Factorize the equation

f(x) = (x + 1)(6x²- 19x + 15)

Expand (6x² - 19x + 15)

f(x) = (x + 1)(6x² - 10x - 9x + 15)

Factorize the expression

f(x) = (x + 1)(2x - 3)(3x - 5)

Hence, the completely factored form of f(x) = 6x³ - 13x² - 4x + 15 is f(x) = (x + 1)(2x - 3)(3x - 5)

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