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ANEK [815]
3 years ago
15

Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25​

Mathematics
1 answer:
Oxana [17]3 years ago
5 0

Answer:

1

Step-by-step explanation:

\huge {625}^{ \frac{3}{8} }  \times  {5}^{ \frac{1}{2} }  \div 25 \\  \\ =  \huge {( {5}^{4})}^{ \frac{3}{8} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\  =   \huge{5}^{ \cancel4 \times  \frac{3}{ \cancel8 \:  \:  \red{ \bold 2}} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\   \huge=  {5}^{ \frac{3}{2} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\ \huge=  {5}^{ \frac{3}{2}  + \frac{1}{2}}  \div  {5}^{2}  \\ \\ \huge=  {5}^{ \frac{4}{2}  }  \div  {5}^{2}  \\ \\ \huge=  {5}^{ 2  }  \div  {5}^{2}  \\  \\   \huge=  {5}^{ 2  - 2 }  \\  \\   \huge=  {5}^{ 0 }  \\  \\   \huge=  1

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andrey2020 [161]

First observe that if a+b>0,

(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}

Let a=0 and b=x. It follows that

a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}

Now let b=1, so a^2+a=4x. Solving for a,

a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2

which means

a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}

Now solve for x.

x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2

(note that we assume 2x-1\ge0)

4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}

(we omit x=0 since 2\cdot0-1=-1\ge0 is not true)

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2 years ago
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4 years ago
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Answer:

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Step-by-step explanation:

Rewrite the first sentence as an equation: (S= Sharla) (P= Patricia)

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