The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
Answer:
False i think
Step-by-step explanation:
Answer:
-5
Step-by-step explanation:
f(-2) means that -2 is going to be our input in this function.
To solve this, simply substitute -2 for x in the expression given.
If f(x) = 3x+1, then f(-2) = 3(-2) + 1
3(-2)+1 = -6+1 = -5
Hope this helped!
Answer:
B) 0.85
Step-by-step explanation:
By definition, complementary angles add to 90 degrees.
The given angle 58 degrees is complementary to 90-58 = 32 degrees. The two angles 58 and 32 add to 90.
Therefore, cos(32) = 0.848 = 0.85
Answer:
Q is not the midpoint of PR
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
If Q is the midpoint of PR
then
PQ=QR
substitute the given values and solve for x
Remember that
----> given problem
substitute the value of x
Compare with the given value of PR
therefore
Q is not the midpoint of PR
