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svetlana [45]
3 years ago
6

A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot was in view for a total of 0.51 s,

and the top-to-bottom height of the window is 2.25 m. How high above the window top did the flowerpot go?
Physics
1 answer:
Gelneren [198K]3 years ago
8 0

The pot spends T = 0.185s going up and 0.185s going down past the window. 
The average speed passing by the window is 2.20 m/0.185s = 11.89 m/s. 
During passage, the pot increases speed by T*g = 0.185*9.81 = 1.815 m/s 
The speed is therefore 12.80 m/s at the bottom of the window and 10.98 m/s at the top of the window. 

The 10.98 m/s speed at the top of the window allows it to rise another 10.98^2/(2g)= 6.15 m past the top of the window

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Devise an experiment using a Landsat satellite and hypothesize<br> results.
guapka [62]

An experiment that involves using a Landsat satellite is given below;

Paddy lands detection through the use of Landsat-8 satellite images and object-based classification in  cape town, South Africa.

<h3>What is the experiment about?</h3>

Rice is known to be one of the most vital  food staples in a lot of countries, especially South Africa . Due to the irrigated rice production that tend to  differs from other kinds of  agricultural fields, this study was said to have created a paddy field mapping model via the use of  phenological aspects, a lot of  satellite sensor data, and also the use of object-based approach.

This study  uses the phonological features of rice plants and also the use of an annual data regarding surface temperature (LST) to make the paddy map.

The core remote sensing data is made up of the yearly LST that is obtained from MODIS and multi-temporal Landsat-8 satellite imagery.

Based on the study, the total  accuracy and kappa coefficient for the pixel-based classification method is seen to be  92% and 0.89.

Hence, An experiment that involves using a Landsat satellite is Paddy lands detection through the use of Landsat-8 satellite images and object-based classification in  cape town, South Africa.

Learn more about Landsat satellite from

brainly.com/question/25656875

#SPJ1

8 0
2 years ago
How much energy is stored in the electric field of a 50-μm-diameter cell with a 7.0-nm-thick cell wall whose dielectric constant
Nady [450]
:<span>  </span><span>Under the assumption that a cell is made up of two concentric spheres you find the surface are of the inside sphere which will be your A. 

You already have your separation and dielectric constant so just use the formula you stated towards the end of your question and you get 8.93x10^-11 Farads which is about 89pF</span>
7 0
3 years ago
Read 2 more answers
• A plastic bag filled with air has a volume of
ratelena [41]

Answer:

The change in the mass of box = 0.01 kg

Volume of air in the polythene bag = Volume of air in the rigid box

Therefore, Volume of air in the box = 0.008 m^3

Now, Density = Mass/ Volume

=> Density = 0.01 / 0.008 = 1.25 Kg / m^3

Explanation:

I looked it up

8 0
2 years ago
A ray of white light moves through the air and strikes the surface of water in a beaker. The index of refraction of the water is
Naily [24]

Answer:

except ii and iii

Explanation:

The angle of reflection is the angle to the normal the white rays strikes the water surface and it is the incidence angle. Since the white light is moving from less dense medium to a denser medium or a medium with a higher refractive index; the angle of refraction will be less than 30 degrees. Total internal reflection cannot occur because the white light is traveling from a less dense medium to a denser medium.

3 0
3 years ago
A cruise ship sails due south at 2.00 m/s while a coast guard patrol boat heads 19.0° north of east at 5.60 m/s. What are the x-
Lilit [14]

Answer:

The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

Explanation:

Given that,

Velocity of ship = 2.00 m/s due south

Velocity of boat = 5.60 m/s due north

Angle = 19.0°

We need to calculate the component

The velocity of the ship in term x and y coordinate

v_{s_{x}}=0

v_{s_{y}}=2.0\ m/s

The velocity of the boat in term x and y coordinate

For x component,

v_{b_{x}}=v_{b}\cos\theta

Put the value into the formula

v_{b_{x}}=5.60\cos19

v_{b_{x}}=5.29\ m/s

For y component,

v_{b_{y}}=v_{b}\sin\theta

Put the value into the formula

v_{b_{y}}=5.60\sin19

v_{b_{y}}=1.82\ m/s

We need to calculate the x-component and y-component of the velocity of the cruise ship relative to the patrol boat

For x component,

v_{sb_{x}}=v_{s_{x}}-v_{b_{x}}

Put the value into the formula

v_{sb_{x}=0-5.29

v_{sb}_{x}=-5.29\ m/s

For y component,

v_{sb_{y}}=v_{s_{y}}-v_{b_{y}}

Put the value into the formula

v_{sb_{x}=2.-1.82

v_{sb}_{x}=0.18\ m/s

Hence, The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

7 0
3 years ago
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