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vekshin1
4 years ago
9

A 1 kg ball and a 10 kg ball are dropped from a height of 10 m at the same time. In the absence of air resistance,

Physics
1 answer:
koban [17]4 years ago
7 0

Answer: A

Explanation: Neglecting air resistance every object will return to the ground at the same interval regardless of their weights, we can say that the objects are undergoing free falls, they are falling under the sole of gravity.

No matter the weight of the objects or the elevation, without significant air resistance, they will reach the ground at the same time.

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The energy of a photon is equal to (what) times (what) of the photon.
hjlf

The energy carried by a photon is equal to

(Planck's Konstant) times (the frequency of the photon) .

Planck's konstant is 6.626 x 10⁻³⁴ m²-kg/s  (rounded)

3 0
3 years ago
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Hello....I need help with this question.
musickatia [10]

Answer:

3.2 m/s²

Explanation:

Acceleration can be calculated as:

v = u + at (where v is final velocity, u is initial velocity, a is acceleration and t is time)

25 m/s  = 9 m/s  + a(5 s)  (a is unknown)

16 m/s  = a(5 s)

a = 3.2 m/s²

We assume that this is a uniform acceleration (meaning that the velocity increases at an equal rate for those 5 seconds).

6 0
3 years ago
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you stretch a spring by a distance of 0.3 m. the spring has a spring constant of 440 n/m. when you release the spring, it snaps
Alina [70]

Answer:

19.8 J

Explanation:

According to the law of conservation of energy, the total mechanical energy of the spring (sum of kinetic energy and elastic potential energy) must be conserved:

K_i + U_i = K_f + U_f (1)

where we have

K_i is the initial kinetic energy of the spring, which is zero because the spring starts from rest (2)

U_i is the elastic potential energy of the spring when it is fully stretched

K_f is the kinetic energy of the spring when it reaches the natural length

U_f is the elastic potential energy of the spring when it reaches its natural length, which is zero because the stretch in this case is zero (3)

So

U_i = \frac{1}{2}k(\Delta x_i)^2

where

k = 440 N/m is the spring constant

\Delta x_i = 0.3 m is the initial stretching of the spring

Substituting,

U_i = \frac{1}{2}(440)(0.3)^2=19.8 J

And so using eq.(1) and keeping in mind (2) and (3) we find

K_f= U_i = 19.8 J

8 0
3 years ago
Using two spring scales, students pull on opposite sides of a dynamic cart at rest. 7 Newtons of force is pulling left and 5 New
kirill [66]

Answer:

The cart will accelerate to the left

Explanation:

The cart is initially at rest. In order to understand its motion, we should consider the net force acting on the cart. We have two forces acting on it:

- A force of 7 N to the left

- A force of 5 N to the right

Therefore, the net force is

F=7 N -5N=2 N

in the direction of the stronger force (so, to the left).

According to Newton's second law:

F=ma

a net force different from zero produces an acceleration of the object, in the same direction as the net force. Therefore, the cart will accelerate to the left.

7 0
3 years ago
5. Calculate the speed of Charlie who runs to the store 5 kilometers away in 40<br> minutes
exis [7]
This depends on what units you need to convert to, but the answer would be approximately 2.083 m/s.

5km/40min = 5000m/40min = 5000m/2400s = 2.083 m/s
7 0
3 years ago
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