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3 years ago

A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its

Physics

1 answer:

fredd [130]3 years ago

6 0

The average acceleration of the cart is $4.75 m/s^2$

Explanation:

The acceleration of an object is given by

$a=\frac{v-u}{t}$

where

v is the final velocity of the object

u is the initial velocity

t is the time elapsed

For the roller coaster cart in the problem, we have:

u = 5 m/s is the initial velocity

v = 24 m/s is the final velocity

t = 4 s is the time elapsed

Solving the equation, we find the acceleration:

$a=\frac{24-5}{4}=4.75 m/s^2$

Learn more about acceleration:

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Determine the frequency of the 2nd harmonic of a spring that has a 3rd harmonic resonance of f3=512 Hz.

Elena L [17]

Answer:

1) 341 Hz

Explanation:

When a string vibrates, it can vibrate with different frequencies, corresponding to different modes of oscillations.

The fundamental frequency is the lowest possible frequency at which the string can vibrate: this occurs when the string oscillate in one segment only.

If the string oscillates in n segments, we say that it is the n-th mode of vibration, or n-th harmonic.

The frequency of the n-th harmonic is given by

$f_n = nf_1$

where

n is the number of the harmonic

$f_1$ is the fundamental frequency

Here we have:

$f_3=512 Hz$ is the frequency of the 3rd harmonic

So the fundamental frequency is

$f_1=\frac{f_3}{3}=\frac{512}{3}=170.7 Hz$

And so, the frequency of the 2nd harmonic is:

$f_2=2f_1=2(170.7)=341.3 Hz$

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4 years ago

Explain what it means when we say a substance is magnetic

Troyanec [42]

Magnetic refers to the forces that attract something.

please vote my answer brainliest. thanks!

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3 years ago

The diagram illustrates the movement of sound waves between an observer and a race car. As the race car drives away from the obs

Andrei [34K]

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3 years ago

A cylinder of mass mm is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the

Zinaida [17]

Answer:

$y = \frac{-f +/- \sqrt{f^{2} +2kmg}}{k}$

Explanation:

Let y₀ be the initial position of the cylinder when the spring is attached and y its position when it is momentarily at rest.From work-kinetic energy principles, The work done by the spring force + work done by friction + work done by gravity = kinetic energy change of the cylinder

work done by the spring force = ¹/₂k(y₀² - y²)

work done by friction = - f(y - y₀)

work done by gravity = mg(y - y₀)

kinetic energy change of the cylinder = ¹/₂m(v₁² - v₀²)

So ¹/₂k(y₀² - y²) - f(y - y₀) + mg(y - y₀) = ¹/₂m(v₁² - v₀²)

Since the cylinder starts at rest, v₀ = 0. Also, when it is momentarily at rest, v₁ = 0

¹/₂k(y₀² - y²) - f(y - y₀) + mg(y - y₀) = ¹/₂m(0² - 0²)

¹/₂k(y₀² - y²) - f(y - y₀) + mg(y - y₀) = 0

¹/₂ky₀² + fy₀ - mgy₀ -¹/₂ky² - fy + mgy = 0

¹/₂ky₀² + fy₀ - mgy₀ = ¹/₂ky² + fy - mgy

Let y₀ = 0, then the left hand side of the equation equals zero. So,

0 = ¹/₂ky² + fy - mgy

¹/₂ky² + fy - mgy = 0

Using the quadratic formula

$y = \frac{-f +/- \sqrt{f^{2} - 4 X\frac{k}{2} X -mg}}{2 X \frac{k}{2} }\\ y = \frac{-f +/- \sqrt{f^{2} +2kmg}}{k}$

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3 years ago

Which part of a circuit changes electrical energy into another form of energy

aniked [119]

Answer:

The reactive part of a circuit changes electrical energy into another form of energy.

Explanation:

The reactive part of a circuit changes electrical energy into another form of energy.

The inductive part of a circuit changes electrical energy to magnetic energy and the capacitive part of a circuit changes electrical energy to electrostatic energy.

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4 years ago