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3 years ago

A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its

Physics

1 answer:

fredd [130]3 years ago

6 0

The average acceleration of the cart is $4.75 m/s^2$

Explanation:

The acceleration of an object is given by

$a=\frac{v-u}{t}$

where

v is the final velocity of the object

u is the initial velocity

t is the time elapsed

For the roller coaster cart in the problem, we have:

u = 5 m/s is the initial velocity

v = 24 m/s is the final velocity

t = 4 s is the time elapsed

Solving the equation, we find the acceleration:

$a=\frac{24-5}{4}=4.75 m/s^2$

Learn more about acceleration:

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If a topographic map included a 6,000 ft. mountain next to an area of low hills, which would best describe the contour lines on

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4 years ago

Determine the total moment of inertia of a merry-go round with 5 children sitting on it. Of the five children, four are seated a

BaLLatris [955]

Answer:

Explanation:

Given that,

We have five children.

Each of mass m =30kg

They sit on a merry go round

Mass of Merry go round M= 150kg

Radius of Merry go round is r =2m

Four children sit at the edge of the merry go round but one child sit at the centre.

The four child that sit at the edge are 2m from the centre of the merry go round but the one at the centre is 0m from the centre

Moment of inertia?

Moment of inertia is given as

I=Σmi•ri²

For the question, the moment of inertia is the combination of inertial of child and the merry go round

I= I(merry go round) + I(four child)+ I(last child)

The merry go round is assumed to be a solid cylinder, so it is going to have the moment of inertia of solid cylinder

Then,

I(merry go round ) =½ Mr²

Also, Four of the child has the same moment of inertia, they are 2m form the centre of the merry go round why the last child has no moment of inertia

I= I(merry go round) + I(four child) +I(last child )

I= ½Mr² + 4mr² + mr'²

I = ½ × 150 ×2² + 4×30×2² + 30×0²

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3 years ago

a 2-kg object is dropped from a height of 1000 m. What is the force of air resistance on the object when it reaches terminal vel

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It stops accelerating when the air resistance is equal to its weight.
That's (m•g)

= (2 kg) • (9.8 m/s^2)

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3 years ago

Modify how could you charge the electric circuit shown below to allow lightbulb a to stay lit even if lightbulb b is removed fro

shepuryov [24]

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3 years ago

The time, t, required to drive a fixed distance varies inversely as the speed, r. It takes 3 hr at a speed of 14 km/h to driv

kenny6666 [7]

Answer:

time taken with speed 23 km/h will be 1.8 hours or 1 hour 48 minutes

Explanation:

Given:

Time is inversely proportional to the speed

mathematically,

t ∝ (1/r)

let the proportionality constant be 'k'

thus,

t = k/r

therefore, for case 1

time = 3 hr

speed = 14 km/hr

3 = k/14

also,

for case 2

let the time be = t

r = 23 km/h

thus,

we have

t = k/23

on dividing equation 2 by 1

we get

$\frac{t}{3}=\frac{k/23}{k/14}$

$t=\frac{14\times3}{23}$

t = 1.8 hr = or 1 hour 48 minutes ( 0.8 hours × 60 minutes/hour = 48 minutes)

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3 years ago