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Masteriza [31]
3 years ago
9

Students were asked to design an experiment to determine what affects the period of a pendulum. Which of the following should be

the dependent variable(s) for the experiment?
A. The angle of the swing

B. The length of the string only

C. The mass of the bob only

D. The length of the string and the mass of the bob
Physics
1 answer:
labwork [276]3 years ago
7 0
The answer is D, the length of a string and mass of the bob
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A string is vibrating between two posts as shown above. Students are to determine the speed of the wave within this string. They
kow [346]

Answer:

The distance between two posts

Explanation:

As the students have already measured the amount of time necessary for the wave to oscillate up and down that is on the string between two posts,They have to measure the speed of the wave.

        ie  v=fλ

<em>They have to measure distance between the posts. </em>

Because wavelength is equal to the distance between the posts ie full length of string.

The frequency of the wave is calculated by

               f= 1/T

Where is the time period which the students have calculated ie the amount of time taken to oscillate up and down,

Thus the wave speed is calculated using formula

            v=λ/T

6 0
3 years ago
Why does an object traveling in a circle at a constant speed always accelerate ?
LUCKY_DIMON [66]
Because "acceleration" doesn't mean "speeding up".  It means any change
in the speed or direction of motion.

An airplane speeding up, a bicycle slowing down, and a car going around a curve, are all doing accelerated motion.

A circle has no straight parts, so an object traveling in a circle is always changing
its direction. That means accelerated motion, even if its speed doesn't change..
6 0
3 years ago
Read 2 more answers
Calculate the speed of your cat as it runs towards its food bowl 14.7m away in 4.5 s. Give answer in mph.
Luden [163]

Answer:

3.26mph

Explanation:

To calculate speed, use the formula distance/time. In this case, just divide 14.7  by 4.5.

4 0
3 years ago
Suppose a star has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 ) but is located at a distance of 300 ligh
iragen [17]

For  a star that has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 is mathematically given as

L=2.7*10^30w

<h3> What is its luminosity?</h3>

Generally, the equation for the luminosity  is mathematically given as

L=4*\pi^2*b

Therefore

L=4*\pi^2*b

L=4* \pi *(2.83*10^{18})*2.7*10^{-8}

L=2.7*10^30

In conclusion, the luminosity

L=2.7*10^30w

Read more about Light

brainly.com/question/25770676

6 0
2 years ago
The polar coordinates of the collar A are given as functions of time in seconds by r = 2+ 0.7 t2 ft and ????= 3.5t rad. What are
r-ruslan [8.4K]

Answer with explanation:

Part a)

v_{radial}=\frac{dr}{dt}=\frac{d(2+0.7t^{2})}{dt}\\\\v_{radial}=1.4t\\\\\therefore v_{radial}|_{t=4}=1.4\times 4=5.6ft/s\\\\v_{angular}=r|_{t=4}\times \frac{d\theta }{dt}=13.2\frac{3.5t}{dt}=46.2fts^{-1}\\\\\therefore v=\sqrt{v_{radial}^{2}+v_{angular}^{2}}\\\\v=46.53ft/s

Part b)

a_{radial}=\frac{d^{2}r}{dt^{2}}=\frac{d^{2}(2+0.7t^{2})}{dt^{2}}\\\\a_{radial}=1.4ft/s^{2}\\\\a_{angular}=r\times \frac{d^{2}\theta }{dt^{2}}\\\\a_{angular}=r\times \frac{d^{2}(3.5t) }{dt^{2}}\\\\\therefore a_{angular}=0\\\\\therefore Accleration=1.4ft/s^{2}

8 0
3 years ago
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