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lara [203]
4 years ago
11

It takes a printer 10 hours to print the class schedules for all of the students in a college. A faster printer can do the job i

n 6 hours. How long will it take to do the job if both printers are used?
Mathematics
1 answer:
kolbaska11 [484]4 years ago
4 0
If for the slower printer it takes 10 hours for the whole thing, how much has it done in  1 hour?  well, since it takes 10 hours total, in 1 hour it has only done 1/10 th of the whole work.

the faster printer however, can do it in 6 total, how much has it done in 1 hour?  well, 1/6 of the whole work.

now, let's say, they both work together, and it takes "t" hours to finish the whole thing with both rolling.

let's add both rates to see how much that is,

\bf \stackrel{slower~printer}{\cfrac{1}{10}}~~+~~\stackrel{faster~printer}{\cfrac{1}{6}}~~=~~\stackrel{1hr~work}{\cfrac{1}{t}}\\\\
-------------------------------\\\\
\textit{LCD is 30}\implies \cfrac{3+5}{30}=\cfrac{1}{t}\implies \cfrac{8}{30}=\cfrac{1}{t}\implies t=\cfrac{30\cdot 1}{80}

which is 3 hours and 45 minutes.
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Solve for n and simplify your answer. 2= - 6/5n<br> I need some help with this
Verizon [17]

Answer:

-1  2/3

Step-by-step explanation:

7 0
4 years ago
In three year's time, Mr Sullivan will be 3 times as old as his daughter. Six years ago, he was 6 times as old as her. How old a
Mkey [24]
S=sullivan's age
d=daughter's age


in 3 years time (s+3 and d+3)
sulivan is 3 times as old as daughter
s+3=3(d+3)

6 years ago (s-6 and d-6)
he was 6 times as old
s-6=6(d-6)

expand

s+3=3d+9
s-6=6d-36
for 2nd equation, add 6 to both sides
s=6d-30
sub 6d+30 for s in other equation
6d-30+3=3d+9
6d-27=3d+9
minus 3d both sides
3d-27=9
add 27 both sides
3d=36
divide both sides by 3
d=12

sub back

s=6d-30
s=6(12)-30
s=72-30
s=42



Mr. Sullivan is 42 now
Daughter is 12 now
5 0
3 years ago
Does 24, 7, and 26 form a right triangle
const2013 [10]

Answer:

No. It is an obtuse triangle.

Step-by-step explanation:

If c^2>a^2+b^2, then the triangle is obtuse. Since 24^2 + 7^2 is 625, and the square root of 625 is 25, that means 26>25. This proves that the triangle is obtuse.

4 0
3 years ago
1) The perimeter of a rectangular classroom floor is 90 feet. The length of the floor is twice the
lana [24]

Answer: The equation would NOT help us solve for the length and width of the classroom is "x + 2y = 90".

Step-by-step explanation:

Let y be the width of the rectangular classroom floor and x be the length of the rectangular classroom floor .

Given ,

The perimeter of a rectangular classroom floor is 90 feet.

The length of the floor is twice the  width.

i.e. Length =2 (width)

i.e. x= 2y ..(i)

Also, perimeter = 2(length+width)

i.e. 2(x+y)=90\\\\\Rightarrow\ 2x+2y=90

When we put value of x from (i), we get

2(2y) + 2y = 90

Hence, the equation would NOT help us solve for the length and width of the classroom is "x + 2y = 90".

8 0
3 years ago
Question 8<br> If h (2) = 2x + 1. find the value of x if h(x) is 11.<br> 5<br> 23<br> -23<br> 7
mel-nik [20]

I think the answer is 23

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7 0
4 years ago
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