<h3>
Answer: P(B) = 7/20</h3>
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Work Shown:
Given info
P(A) = 7/20
P(A∩B)=49/400
P(B) = unknown
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P(A∩B) = P(A)*P(B), assuming A and B are independent events
49/400 = (7/20)*P(B)
(7/20)*P(B) = 49/400
P(B) = (20/7)(49/400)
P(B) = (20*49)/(7*400)
P(B) = (20*7*7)/(7*20*20)
P(B) = 7/20
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Note how
P(A∩B) = P(A)*P(B)
P(A∩B) = (7/20)*(7/20)
P(A∩B) = (7*7)/(20*20)
P(A∩B) = 49/400
which helps to confirm the answer.
So what is your question?
(4x³+ 13x − 7) − (6x²<span>+ 9x + 2)
Remember that if they don't have the same exponents/bases (x</span>²,x³, etc.), then they cannot be grouped together.
This means that 4x³ and 6x² will be left alone because there are no other x² or x³ in the expression.
So first thing you do is distribute. Don't forget about that - in front of the second parentheses.
(4x³+ 13x − 7) − (6x²+ 9x + 2)
(4x³ + 13x − 7) + (−6x² - 9x - 2)
4x³ - 6x² + (13x - 7) + (-9x - 2)
4x³ - 6x² + 4x (- 7) + (- 2)
4x³ - 6x² + 4x - 9
So the answer is:
C. <span>4x3− 6x2+ 4x − 9</span>
Answer:
1/5
Step-by-step explanation:
For 27,the temp and time increase
