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2 years ago

No links pls

Mathematics

1 answer:

asambeis [7]2 years ago

3 0

Answer:

Positive 1 over 6 raised to the 2nd power 1/62 or 1 over 36 which is 1/36. To find -6-2, take the inverse of -62.

(first find -62) -62 = -6 * -6 = 36

(then take the inverse of 36, which is 1 over 36) = 1 / 36 = 0.0277

so, -6-2 =0.0277

Step-by-step explanation:

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An exterior angle of a regular convex polygon is 40°. What is the number of sides of the polygon?

seraphim [82]

Answer:

option B

Step-by-step explanation:

Sum of interior angles of a polygon with n sides:

$= (n - 2 )\times 180$

$Therefore, Each \ interior \ angle = (\frac{n - 2}{n} )\times 180$

$Sum \ of \ one \ of \ the \ interior \ angle \ with \ its \ exterior \ angle \ is \ 180^\circ$

$[ \ because \ straight \ line \ angle = 180^\circ \ ]$

That is ,

$Exterior \ angle + Interior \ angle = 180^\circ\\\\40^ \circ + (\frac{n-2}{n}) \times 180 = 180^\circ\\\\40 n + 180n - 360 = 180n\\\\40n = 180n - 180n + 360 \\\\40n = 360 \\\\n = 9$

Sum of exterior angles of a regular polygon = 360

Given 1 exterior angle of the regular polygon is 40

Therefore ,

$n \times 40 = 360\\\\n = \frac{360}{40} \\\\n = 9$

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2 years ago

Evaluate 18 -8(14 + 4) + 42.

Alina [70]

Answer:

-84

Step-by-step explanation:

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3 years ago

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AlekseyPX

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Step-by-step explanation:

6 0

2 years ago

Evaluate the integral by making an appropriate change of variables.

VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

u = y + x

v = y - x

Solving for x and y, we would have

x = (u - v)/2

y = (u + v)/2

in which case the Jacobian and its determinant are

$J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12$

The trapezoid R has two of its edges on the lines x + y = 8 and x + y = 9, so right away, we have 8 ≤ u ≤ 9.

Then for v, we observe that when x = 0 (the lowest edge of R), v = y ; similarly, when y = 0 (the leftmost edge of R), v = -x. So

-x ≤ v ≤ y

-(u - v)/2 ≤ v ≤ (u + v)/2

-u + v ≤ 2v ≤ u + v

-u ≤ v ≤ u

So, the integral becomes

$\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du$

$=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du$

$=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du$

$=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}$

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2 years ago

Rewrite in slope intercept a(bx + y) = c

GrogVix [38]

Y=abx +c ……………..loll

8 0

2 years ago