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Gwar [14]
4 years ago
9

Kim's softball team was playing in the championship game. When there were 4 innings left, the team was losing by a score of 17 t

o 6 points. In the last 4 innings, her team scored the same number of points per inning, and the other team did not score any more points. Kim's team won with the most points. Write an inequality to determine the number of points per inning, ppp, Kim's team could have scored. Write an inequality to determine the number of points per inning, ppp, Kim's team could have scor Find the minimum whole number of points per inning Kim's team could have scored.
Mathematics
1 answer:
satela [25.4K]4 years ago
8 0

Answer:

3

Step-by-step explanation:

Given the following :

Score when there were 4 innings left = 17 to 6

Kim's team = 6 ; opposition team = 17

Opposition didn't score any point in the last 4 innings

Kim's team scored same number of points per inning and also won with the most points

Minimum Number of points Kim's team could have scored per inning :

Let number of points scored in each of the last 4 innings = p

Since they also won eventually:

Then

4p + initial points > opposition point

4p + 6 > 17

4p > 17 - 6

4p > 11

p > 11/4

p > 2.75

Hence, the minimum number of points Kim's team could have scored per inning in the last 4 would be 3( nearest whole number)

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The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
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Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

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• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

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By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

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\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
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Answer:

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