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Arada [10]
3 years ago
5

A line passes through the points (2,-4) and (6,10). What is the equation of the line?

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer:

y = \frac{7}{2} x - 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, - 4) and (x₂, y₂ ) = (6, 10)

m = \frac{10+4}{6-2} = \frac{14}{4} = \frac{7}{2} , thus

y = \frac{7}{2} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, - 4) , then

- 4 = 7 + c ⇒ c = - 4 - 7 = - 11

y = \frac{7}{2} x - 11 ← equation of line

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Which of these are coordinates for parts of the Ranger Station​
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ANSWER

F (2,3)

EXPLANATION

The coordinates are ordered pairs.

So the x-coordinate comes first and the y-coordinate second.

In other words the coordinate on the horizontal axis comes first and that of the vertical axis comes second.

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(2,3),(2,4),(3,3),(3,4)

The correct choice is F.

6 0
3 years ago
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Abigail has 17 chocolates left.As she offers her friend a chocolate she realises there are now only 2 of her favourite truffles
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Answer:

there will be  a 2/17 chance that she will get her favorite truffle.

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Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

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Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

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D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

8 0
3 years ago
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As with a system of equations, call them A and B in order to keep them straight.

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With y = 2 we can substitute that back into an original equation. Choose B.

x = y + 3

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x = 5


Thus x = 5 and y = 2, or (5, 2) is the solution of this system.

7 0
3 years ago
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