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Nadusha1986 [10]
3 years ago
6

19/100 x g/10 help please :0

Mathematics
1 answer:
Rudik [331]3 years ago
4 0

19g/1000 would be the right answer when simplified.

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PLEASE HELP ME. I DONT WANT TO FAIL. <br>​
Over [174]

Answer:

A.) 138.85             D.) 87.85

Step-by-step explanation:

64.98 + 73.87 = 138.85

64.98 + 73.87 - 51.00

138.85 - 51.00 = 87.85

7 0
3 years ago
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Soo uhh ye I need help-
maxonik [38]
Remember PEMDAS.

P=parenthesis
E=exponents
M=multiplication
D=division
A=addition
S=subtraction
7 0
3 years ago
Find the domain of the graphed function. Help me please);
pogonyaev

The correct answer is B. -4<x<2.

This is because the domain is looking for the values of x that can be used in the function. In the picture below, you will notice that the leftmost point is at x = -4. This is as low as the x value goes. The rightmost point is at x = 2, which is as large as the x value gets. Therefore the domain is between those two numbers.

8 0
3 years ago
The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)
sveticcg [70]

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

  • The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
  • The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
  • If x and y coordinates are positive, then the angle lies in the 1st quadrant
  • If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
  • If x and y coordinates are negative, then the angle lies in the 3rd quadrant
  • If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point (\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = \frac{-\sqrt{2} }{2}

∴ cosФ = \frac{-\sqrt{2} }{2}

∵ y-coordinate = \frac{\sqrt{2} }{2}

∴ sinФ = \frac{\sqrt{2} }{2}

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = \frac{-\sqrt{2} }{2} ÷ \frac{\sqrt{2} }{2}

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

4 0
3 years ago
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E is the midpoint of DF. IF DE = x + 5 and DF = 3x + 2, what is DF?
prisoha [69]

Answer:

13

Step-by-step explanation:

x+5=3x+2

5=2x+2

3=2x

x=1.5

1.5+5=6.5

6.5 is half of DF, DF=13

6 0
3 years ago
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