Ciekawostka

1 answer:

4 0

Traders have invested $ 100,000 in the Peace Garden Center to boost the capital Mogadishu and make a profit. looga farm income to make people come to the door to take the free tickets for different values $ 0.8 adults and 0.6 children. As many as 150 tickets were sold on Friday for $ 102. produce more child tickets than adult tickets?

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Paul owes Paula 35 cents and has a pocket full of 5-cent coins, 10-cent coins, and 25-cent coins that he can use to pay her. Wha

kykrilka [37]

So, what is the case in which he uses the least coins? can he use 1 coin? no, there isn't a 35 cent coin. can he use 2 coins? yes! he can use 25+10 cent coins!

now, the largest number of coins means the coins of the smallest value: so using only 5 cent coins. How many would this be?

we have to divide:

35/5=7

so we would use 7 coins.

And the difference is 5: 7-2 is 5.

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2 years ago

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erastovalidia [21]

Answer:

12,500 square millimeters

Step-by-step explanation:

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3 years ago

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Ali runs five days a week at the local park's nature trail. The circular trail is 440 yards long. Each day that Ali runs, she ru

SpyIntel [72]

Answer:

15 miles

Step-by-step explanation:

12 * 440 = 5280 (yards every day)

5280 * 5 = 26400 (yards per week)

26400 *0.000568182 = 15 miles

8 0

2 years ago

Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

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2 years ago

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Vitek1552 [10]

It would be all the evens since the reference is x^2... it’s not the odds Bc it’s not a graph like or
So jt would be 4,6,8

Hope it helps
Ps I’m not positive, haven’t done this for a while now

7 0

2 years ago

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