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lys-0071 [83]
3 years ago
14

How many distinguishable a arrangements are there of the letters in "REPRESENTATION"?

Mathematics
1 answer:
Anika [276]3 years ago
5 0

Answer: There are 1,816,214,400 ways for arrangements.

Step-by-step explanation:

Since we have given that

"REPRESENTATION"

Here, number of letters = 14

There are 2 R's, 3 E's, 2 T's, 2 N's

So, number of permutations would be

\dfrac{14!}{2!\times 3!\times 2!\times 2!}\\\\=1,816,214,400

Hence, there are 1,816,214,400 ways for arrangements.

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Solve the system of equations by multiplying and adding. Enter the solution as an ordered pair.
GREYUIT [131]

Answer:

(x, y) = (- 3, 4)

Step-by-step explanation:

Given the 2 equations

5x + 2y = - 7 → (1)

4x - y = - 16 → (2)

multiply all terms in (2) by 2

8x - 2y = - 32 → (3)

Add (1) and (3) term by term

(5x + 8x) + (2y - 2y) = (- 7 - 32)

13x = - 39 ( divide both sides by 13 )

x = - 3

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substituting in (1) gives

(5 × - 3) + 2y = - 7

- 15 + 2y = - 7 ( add 15 to both sides )

2y = 8 ( divide both sides by 2 )

y = 4

solution is (- 3, 4 )


3 0
3 years ago
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kicyunya [14]
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Step-by-step explanation:

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