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quester [9]
3 years ago
15

Evaluate the expression (4x^3)^2 for x=2 A.128 B.512 C.256 D. 1024

Mathematics
2 answers:
julsineya [31]3 years ago
8 0

Answer:

d:) 1024

Step-by-step explanation:

Evaluate (4 x^3)^2 where x = 2:

(4 x^3)^2 = (4×2^3)^2

Multiply each exponent in 4×2^3 by 2:

4^2 (2^3)^2

Multiply exponents. (2^3)^2 = 2^(3×2):

2^(3×2)×4^2

4^2 = 16:

2^(3×2)×16

3×2 = 6:

2^6×16

2^6 = (2^3)^2 = (2×2^2)^2:

(2×2^2)^2 16

2^2 = 4:

(2×4)^2 16

2×4 = 8:

8^2×16

8^2 = 64:

64×16

| | 6 | 4

× | | 1 | 6

| 3 | 8 | 4

| 6 | 4 | 0

1 | 0 | 2 | 4:

Answer:  1024

padilas [110]3 years ago
5 0
Your answer is D Bc first you solve the explanation step by step,multiply the exponents ,multiply again ,and that’s how you solve this problem
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The coordinates of which point are (–3, –6)? On a coordinate plane, point A is (negative 3, 6), point B is (negative 6, negative
julia-pushkina [17]

Answer:

Point c

Step-by-step explanation:

3 0
3 years ago
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Can someone help me with this math question & show steps ?
forsale [732]

a xuz if u work it out ull get a

7 0
3 years ago
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(c) The total number of one centimeter lines in the first n diagrams is given by the expression
trapecia [35]

Answer:

I) f + g = 10/3

II) 4f + 2g = 20/3

III) f = 2 and g = 4/3

Step-by-step explanation:

From the chart,

P = 25

q = 40

The total number of one centimeter lines in the first n diagrams is given by the expression 

2/3n^3 + fn^2 + gn. 

When n = 1, the total number of line = 4. So,

2/3(1)^3 + f(1)^2 + g(1) = 4

2/3 + f + g = 4

Make f+g the subject of formula

f + g = 4 - 2/3

f + g = (12 - 2)/3

f + g = 10/3 ......(1)

When n = 2

Total number of line = 12

2/3(2)^3 + f(2)^2 + g(2) = 12

2/3×8 + 4f + 2g = 12

16/3 + 4f + 2g = 12

4f + 2g = 12 - 16/3

4f + 2g = (36 - 16)/3

4f + 2g = 20/3 ......(2)

(iii) To find the values of f and g, solve equation 1 and 2 simultaneously

f + g = 10/3 × 2

4f + 2g = 32/3

2f + 2g = 20/3

4f + 2g = 32/3

- 2f = - 12/3

f = 12/6

f = 2

Substitutes f in equation 1

f + g = 10/3

2 + g = 10/3

g = 10/3 - 2

g = (10 - 6)/3

g = 4/3

4 0
3 years ago
10 points.
rusak2 [61]

Answer:

<u>The difference between the experimental probability and the theoretical probability is 0.08 (rounding the answer to the nearest hundredth) or 8%.</u>

Correct statement and question:

Regina has a bag of 6 orange marbles and 6 black marbles. She picks a marble at random and then puts it back in the bag. She does this 24 times. The results can be found in the table.

Outcome Tally

Orange  10

Black     14

Figure out the percent error of pulling a black marble in Regina’s experiment. Show your work and round the answer to the nearest hundredth.

Source:

Previous question that can be found at brainly

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of orange marbles = 6

Number of black marbles = 6

Number of times of the experiment = 24

Number of times the outcome was an orange marble = 10

Number of times the outcome was a black marble  = 14

2. Figure out the percent error of pulling a black marble in Regina’s experiment. Show your work and round the answer to the nearest hundredth.

The theoretical probability of pulling a black marble is 12/24 or 0.5, given that the number of orange and black marbles are equal and actually, the experimental probability is 14/24 or 0.5833.

We can't describe this difference as an "error". What happened here is that there is a difference between the experimental probability and the theoretical probability.

0.5833 - 0.5 = 0.0833 = 0.08 (rounding the answer to the nearest hundredth)

<u>The difference between the experimental probability and the theoretical probability is 0.08 (rounding the answer to the nearest hundredth) or 8%.</u>

5 0
3 years ago
The sum of the angle measures of a polygon with n sides is 1260. find n.
Murrr4er [49]
Knowing the interior angle sum formula is; 

180x(n-2)

180x(n-2)=1260 (solve for n here) 
180n-360=1260 
180n=1260+360
180n=1620 
n=1620/180 
n=9

Therefore, this polygon has 9 sides.

Hope I helped :) 
4 0
3 years ago
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