For Part A, what to do first is to equate the given equation to zero in order to find your x intercepts (zeroes)
0=-250n^2+3,250n-9,000 after factoring out, we get
-250(n-4)(n-9) and these are your zero values.
For Part B, you need to square the function from the general equation Ax^2+Bx+C=0. So to do that, we use the equated form of the equation 0=-250n^2+3,250n-9,000 and in order to have a positive value of 250n^2, we divide both sides by -1
250n^2-3,250n+9,000=0
to simplify, we divide it by 250 to get n^2-13n+36=0 or n^2-13n = -36 (this form is easier in order to complete the square, ax^2+bx=c)
in squaring, we need to apply <span><span><span>(<span>b/2</span>)^2 to both sides where our b is -13 so,
(-13/2)^2 is 169/4
so the equation now becomes n^2-13n+169/4 = 25/4 or to simplify, we apply the concept of a perfect square binomial, so the equation turns out like this
(n-13/2)^2 = 25/4 then to find the value of n, we apply the square root to both sides to obtain n-13/2 = 5/2 and n is 9. This gives us the confirmation from Part A.
For Part C, since the function is a binomial so the graph is a parabola. The axis of symmetry would be x=5.
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Is it 89 ? Wouldn’t you just add them up from the starting point ?
If all students scored the same the score of each student would be 4.5.
3,500 is the best estimate if you multiply 7 by round 456 to 500 so 7x500=3,500
