Answer:
b. Yes, probability is > 0.05
Step-by-step explanation:
We have to find P(X=3) and if the probability is below 0.05 then the it would be unusual and if it isn't below 0.05 we believe that the data from the blood program.
This probability can be found bu binomial distribution with parameters n=6
and p=0.4.
P(X=x)=nCx(p^x)(q^n-x)
where q=1-p=1-0.4=0.6.
P(X=3)=6C3(0.4^3)(0.6^3)
P(X=3)=20(0.064)(0.216)
P(X=3)=0.27648
As the probability that the three have a blood group is greater than 0.05, so, we believe that the data from the blood program.
