X^3-2x is an algebraic expression. Note that there is NO "=" sign here.
x^4 + 4x^2 + 4 = 0 is an algebraic equation. Note the presence of an "=" sign.
Answer:
x+5y =30
this is random because it wont let me submit the answer unless I write 20 characters lol
First move the 13 to the left by subtracting 13 from both sides and setting the 'now expression' equal to zero
p² - 12p - 13
Do the opposite of FOIL (for you are trying to find the numbers being FOILed)
p² - 12p - 13
Find the multiplies of the outside numbers/variables, that, when added (or subtracted, will give you the inside expression
p² - 12p - 13
p -13
p 1
(p - 13)(p + 1)
Set these two expressions equal to zero
p - 13 = 0
p - 13 (+13) = 0 (+13)
p = 13
p + 1 = 0
p + 1 (-1) = 0 (-1)
p = -1
Your answers: p = -1, 13
hope this helps
Answer:
20%
Step-by-step explanation:
3.5 - 2.8 = 0.7
0.7 ÷ 3.5 = 0.2
0.2 × 100 = 20
The answer is 20%.
Hope this helped.
Suppose that a natural number n is neither a prime nor a perfect square. Then, there exist natural numbers p and q such that p < n, q < n , p ≠ q and pq = n.
Now, note that (n - 1)! = (n - 1)(n - 2)(n - 3)...(3)(2)(1).
Since p < n and q < n, p = (n - k) and q = (n - l) where k ≠ l and k, l ∈ {∈1, 2, 3, ... , n - 1}. But we know that (n - k)(n - l) | (n - 1)!
Hence, pq | (n - 1)! and therefore n | (n - 1)!
Hence, any natural number n is either prime, a complete square or divides (n - 1)!, as required.
