Hello :
the terme general is : an = a1 +(n-1)d
a11 = a1+(11-1)×5
a11 = -12+50
a11 = 38
<span>the sum of the first 11 terms is : S11 = (11/2)(a1+a11)
</span>S11 = (11/2)(-12+38)
S11 = 143
Answer:
D. x = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Leg <em>a</em> = 8
Leg <em>b</em> = <em>x</em>
Hypotenuse <em>c</em> = 10
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [PT]: 8² + x² = 10²
- Isolate <em>x</em> term: x² = 10² - 8²
- Exponents: x² = 100 - 64
- Subtract: x² = 36
- Isolate <em>x</em>: x = 6
Answer:
erm
Step-by-step explanation:
(8,8000)
Answer:
B,AD
Step-by-step explanation:
BECAUSE I SAY IT
First, keep in mind that two negatives make a positive:
-13w^2 + 13 + 2w^2
-11w^2 + 13
