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3 years ago

What is 12/16 reduced?

Mathematics

2 answers:

VashaNatasha [74]3 years ago

5 0

12/16 The reduced form is 3/4 because

12/4=3
16/4=4

levacccp [35]3 years ago

3 0

3/4
You can divide both of them by 4. 12/4= 3 and 16/4= 4 Youre welcome

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Julia has 14 pounds of nuts .there are 16 ounces in one pound. how mant ounces of nuts does she have

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There are 14 pounds of nuts, and each are 16 ounces.

14*16 = ?

14*16 = 224

Final answer: She has a total of 224 ounces of nuts.

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John has $4000 in his savings account.each month he withdraws $70 from his account which is the type of function that models thi

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Answer:

y = 4000 - 70x

Linear function.

Step-by-step explanation:

Let x = number of weeks.

In 1 week, he withdraws $70.

That means -70 in 1 week.

After the second week, he will have withdrawn 2 times $70, or

-70 × 2

After 3 week, he will have withdrawn -70 × 3

After x weeks, he will have withdrawn $70 × x,or simply -70x.

He starts with 4000, so after x weeks, he has 4000 - 7x.

Let y = the amount of money at week x.

The equation is

y = 4000 - 70x

This is a linear function.

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3 years ago

A teacher buys packs of notebooks to give to his students. The ratio of gold notebooks to red notebooks is represented in the ta

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Answer:

there would be 40 gold notebooks

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3 years ago

A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

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Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

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3 years ago